我研究了这个并且没有找到答案,所以我认为这里有人可以解释一下。我试图创建一个返回的数据表,显示按周数分组的每个用户的游戏数量。
id | user | team | week_number
----+---------+-----------+-------------
1 | john | eagles | 1
2 | john | saints | 1
3 | harry | patriots | 1
4 | frank | cowboys | 1
5 | john | falcons | 2
6 | frank | cardinals| 2
week_number | frank | harry | john
------------+-------+-------+-------
1 | 1 | 1 | 2
2 | 1 | 0 | 1
我将使用PHP
来显示输出。
答案 0 :(得分:1)
您所需输出的替代方法可能是:
WEEK_NUMBER USER GAMES
1 frank 1
1 harry 1
1 john 2
2 frank 1
2 john 1
如果此输出可以为您工作,那么您可以运行以下查询:
select week_number,user,count(team) as games from table
group by week_number,user;
答案 1 :(得分:0)
在我的头撞墙后,我得到启发并最终得到了询问。 ;)
你可以运行它来实现你想要的输出:
SELECT T.week_number,
IFNULL(SUM((CASE WHEN T.user = 'frank' THEN T.games END)),0) frank,
IFNULL(SUM((CASE WHEN T.user = 'harry' THEN T.games END)),0) harry,
IFNULL(SUM((CASE WHEN T.user = 'john' THEN T.games END)),0) john
FROM (select week_number,user,count(team) as games from table_name group by week_number,user) as T
GROUP BY week_number