Question

我有2个按钮：button1和button2。我想为每个触摸的对应按钮创建一个NSSet，并且想要在触摸按钮2时显示set1值，反之亦然。按下按钮1时仅设置1打印，按下按钮2时仅设置2。如何保留在button1动作中创建的设置，以便在按下按钮2时可以显示/使用它。看看我的简单代码

在实施中，我有：

- (IBAction)button1:(UIButton *)sender {

    //somecode

    selectionButton1 = [[NSMutableArray alloc ] initWithObjects:@0,@1,@1,@4,@6,@11, nil];

    NSMutableSet *set1 = [NSMutableSet setWithArray: selectionButton1];
    NSLog(@"selectionButton1  = %@", set1);
    NSLog(@"selectionButton2  = %@", set2);
}


- (IBAction)button2:(UIButton *) sender {

    //somecode

    selectionButton2 = [[NSMutableArray alloc ] initWithObjects:@0,@5,@6,@7,@8,@10, nil];
    NSMutableSet *set2 = [NSMutableSet setWithArray: selectionButton2];
    NSLog(@"selectionButton1  = %@", set1);
    NSLog(@"selectionButton2  = %@", set2);
}

Answer 1

为你的套装制作属性。如果您不需要从其他类访问它们，请在.m文件的私有类扩展中创建它们的内部属性。然后使用self.propertyName访问属性：

<强> MyClass.m：

@interface MyClass // Declares a private class extension

@property (strong, nonatomic) NSMutableSet *set1;
@property (strong, nonatomic) NSMutableSet *set2

@end

@implementation MyClass

- (IBAction)button1:(UIButton *)sender {

    //somecode

    selectionButton1 = [[NSMutableArray alloc ] initWithObjects:@0,@1,@1,@4,@6,@11, nil];

    self.set1 = [NSMutableSet setWithArray: selectionButton1];
    NSLog(@"selectionButton1  = %@", self.set1);
    NSLog(@"selectionButton2  = %@", self.set2);
}


- (IBAction)button2:(UIButton *) sender {

    //somecode

    selectionButton2 = [[NSMutableArray alloc ] initWithObjects:@0,@5,@6,@7,@8,@10, nil];
    self.set2 = [NSMutableSet setWithArray: selectionButton2];
    NSLog(@"selectionButton1  = %@", self.set1);
    NSLog(@"selectionButton2  = %@", self.set2);
}

@end

有关属性的更多信息，请参阅Apple’s documentation。

保留我新创建的NSSet

1 个答案: