Question

我有一个数组如下

#bad
tourney = [
  [
    [["Armando", "P"], ["Dave", "S"]],      
    [["Richard", "R"], ["Michael", "S"]]
  ],
  [
    [["Allen", "S"], ["Omer", "P"]],
    [["David E.", "R"], ["Richard X.", "P"]]
  ]
]

我必须实施一种递归锦标赛方法，让每个竞争对手彼此对抗。只要它的2 ^ n，这场比赛必须增加到任何数字。是否有任何数组方法将此数组分成两个级别，如下面的数组？

#good
tourney = [
  ["Armando", "P"], ["Dave", "S"],
  ["Richard", "R"], ["Michael", "S"],
  ["Allen", "S"], ["Omer", "P"],
  ["David E.", "R"], ["Richard X.", "P"]
]

有了这个，我可以使用each_slice(2)让对手相互对抗。

解决

以下是我能够提出来的。

def split(array)
  return array.flatten(1)
end

def depth_array(a)
  return 0 unless a.is_a?(Array)
  return 1+depth_array(a[0])
end

def format_array(array)
  good = array
  while depth_array(good) > 2
    good = split(good)
  end
end

tourney = [[[["Armando", "P"], ["Dave", "S"]],      

       [["Richard", "R"], ["Michael", "S"]]],

       [[["Allen", "S"], ["Omer", "P"]],

       [["David E.", "R"], ["Richard X.", "P"]]]]

tourney2 = [[["Armando", "P"], ["Dave", "S"]], 

        [["Allen", "S"], ["Omer", "P"]]]

tourney3 = [["Omer", "P"], ["Allen", "S"]]

tourney4 = [[[[["Armando", "P"], ["Armando", "P"]], [["Armando", "P"], ["Armando", "P"]]], 

         [[["Allen", "S"], ["Allen", "S"]], [["Allen", "S"], ["Allen", "S"]]]], 

         [[[["Dave", "S"], ["Dave", "S"]], [["Dave", "S"], ["Dave", "S"]]], 

          [[["David E.", "R"], ["David E.", "R"]], [["David E.", "R"], ["David E.", "R"]]]]]



format_array(tourney4)

Answer 1

tourney.flatten(2)将坏数组转换为好数组。

Answer 2

这样的事情怎么样：

tourney = [[[["Armando", "P"], ["Dave", "S"]],      
           [["Richard", "R"], ["Michael", "S"]]],
           [[["Allen", "S"], ["Omer", "P"]],
           [["David E.", "R"], ["Richard X.", "P"]]]]

good = [].tap do |arr|
  tourney.flatten.each_slice(2) do |pr|
    arr << pr
  end
end

puts good.inspect

# output 
[["Armando", "P"], ["Dave", "S"], ["Richard", "R"], ["Michael", "S"], ["Allen", "S"], ["Omer", "P"], ["David E.", "R"], ["Richard X.", "P"]]

如何按特定格式拆分多层阵列

解决

2 个答案: