#include "stdafx.h"
#include<iostream>
using namespace std;
class bank
{
public: char name[20];
public: float balance;
public: void get()
{
cout << "\nEnter name and balance in Account respectively\n";
cin >> name >> balance;
}
public: void display()
{
cout << "Name: " << name << " Balance: " << balance;
}
};
void main()
{
int i = 0;
bank b[10];
bank max;
bank temp;
for (i = 0; i < 10; i++)
{
b[i].get();
}
for (i = 0; i < 10; i++)
{
if (b[i + 1].balance > b[i].balance)
{
max.balance = b[i + 1].balance;
max.name = b[i + 1].name;//Error 1 error C2106: '=' : left operand must be l-value
}
else
{
temp.balance = b[i + 1].balance;
temp.name = b[i + 1].name;//Error 2 error C2106: '=' : left operand must be l-value
b[i + 1].balance = b[i].balance;
b[i + 1].name = b[i].name;//Error 3 error C2106: '=' : left operand must be l-value
b[i].balance = temp.balance;
b[i].name = temp.name;//Error 4 error C2106: '=' : left operand must be l-value
max.balance = b[i + 1].balance;
max.name = b[i + 1].name;//Error 5 error C2106: '=' : left operand must be l-value
}
}
max.display();
}
在这个程序中,我将输入作为10人的名字和余额,并将输出显示为与最高余额相对应的名称和余额。 除了代码本身作为注释显示的错误之外,我还在相同的那些行中获得另一个代码,只有我对错误发表评论。另一个错误是:
IntelliSense: expression must be a modifiable lvalue
我正在使用Visual Studio Professional 2013,代码在Visual C ++中
答案 0 :(得分:1)
您无法将char[]
变量分配给另一个char[]
变量。您应该使用strcpy
函数来执行此操作(并且不要忘记先include<cstring>
)。看到这个
how to copy char array to another char array in C?有待进一步说明。
如果它改变如此,那应该没问题:
#include<iostream>
#include<cstring>
using namespace std;
class bank
{
public: char name[20];
public: float balance;
public: void get()
{
cout << "\nEnter name and balance in Account respectively\n";
cin >> name >> balance;
}
public: void display()
{
cout << "Name: " << name << " Balance: " << balance;
}
};
void main()
{
int i = 0;
bank b[10];
bank max;
bank temp;
char tempstr[20]; // use this for temporary string
for (i = 0; i < 3; i++)
{
b[i].get();
}
for (i = 0; i < 2; i++) // you should change the upper bound to 9
// so it not crash when i = 9
{
if (b[i + 1].balance > b[i].balance)
{
max.balance = b[i + 1].balance;
strcpy(max.name, b[i+1].name); // use strcpy
}
else
{
temp.balance = b[i + 1].balance;
strcpy(temp.name, b[i+1].name); // use strcpy
b[i + 1].balance = b[i].balance;
strcpy(b[i+1].name, b[i].name); // use strcpy
b[i].balance = temp.balance;
strcpy(b[i].name, temp.name); // use strcpy
max.balance = b[i + 1].balance;
strcpy(max.name, b[i+1].name); // use strcpy
}
}
max.display();
}