仅返回数据集中的最新记录

Question

我有一个查询返回几个日期的数据。

我想仅返回SAPOD字段中最近日期的记录（日期实际上是CYYMMDD，其中C = 0之前的2000和2000之后的1，我可以使用SAPOD=Case when LEFT(SAPOD,1)=1 then '20' else '19' end + SUBSTRING(cast(sapod as nvarchar(7)),2,7)将其显示为YYYYMMDD）< / p>

这是我的查询：

SELECT GFCUS, Ne.NEEAN, SCDLE, SAPOD, SATCD,CUS.GFCUN, BGCFN1, 
    BGCFN2, BGCFN3, SV.SVCSA, SV.SVNA1, SV.SVNA2, SV.SVNA3, 
     SV.SVNA4, SV.SVNA5, SV.SVPZIP, SV.NONUK
FROM SCPF ACC 
    INNER JOIN GFPF CUS ON GFCPNC = SCAN
    LEFT OUTER JOIN SXPF SEQ ON SXCUS = GFCUS AND SXPRIM = ''
    LEFT OUTER JOIN SVPFClean SV ON SVSEQ = SXSEQ
    LEFT OUTER JOIN BGPF ON BGCUS = GFCUS AND BGCLC = GFCLC
    LEFT OUTER JOIN NEPF NE ON SCAB=NE.NEAB and SCAN=ne.NEAN and SCAS=ne.NEAS
    LEFT OUTER JOIN SAPF SA ON SCAB=SAAB and SCAN=SAAN and SCAS=SAAS
WHERE 
    (SATCD>500 and
    scsac='IV' and
    scbal = 0 and
    scai30<>'Y' and
    scai14<>'Y' and
    not exists(select * from v5pf where v5and=scan and v5bal<>0))
GROUP BY GFCUS, Ne.NEEAN, SCDLE, SAPOD, SATCD,
    CUS.GFCUN, BGCFN1, BGCFN2, BGCFN3, SV.SVCSA, 
     SV.SVNA1, SV.SVNA2, SV.SVNA3, SV.SVNA4, SV.SVNA5, SV.SVPZIP, SV.NONUK
ORDER BY MAX(SCAN) ASC, SAPOD DESC

我得到的结果如下所示，客户有多笔交易，我们只想显示最近交易的数据：

那么我怎样才能显示最近的交易？这是我应该使用OUTER APPLY还是CROSS APPY？

的情况

修改

对不起我应该澄清，我需要字段NEEAN中每个唯一记录的最新日期，即帐号

Answer 1

您可以按如下方式使用ROW_NUMBER（）：

SELECT
    ROW_NUMBER() OVER (PARTITION BY Ne.NEEAN ORDER BY SAPOD DESC) AS [Row],
    GFCUS, Ne.NEEAN, SCDLE, SAPOD, SATCD,CUS.GFCUN, BGCFN1, 
    BGCFN2, BGCFN3, SV.SVCSA, SV.SVNA1, SV.SVNA2, SV.SVNA3, 
    SV.SVNA4, SV.SVNA5, SV.SVPZIP, SV.NONUK
FROM SCPF ACC 
    INNER JOIN GFPF CUS ON GFCPNC = SCAN
    LEFT OUTER JOIN SXPF SEQ ON SXCUS = GFCUS AND SXPRIM = ''
    LEFT OUTER JOIN SVPFClean SV ON SVSEQ = SXSEQ
    LEFT OUTER JOIN BGPF ON BGCUS = GFCUS AND BGCLC = GFCLC
    LEFT OUTER JOIN NEPF NE ON SCAB=NE.NEAB and SCAN=ne.NEAN and SCAS=ne.NEAS
    LEFT OUTER JOIN SAPF SA ON SCAB=SAAB and SCAN=SAAN and SCAS=SAAS
WHERE 
    (SATCD>500 and
    scsac='IV' and
    scbal = 0 and
    scai30<>'Y' and
    scai14<>'Y' and
    not exists(select * from v5pf where v5and=scan and v5bal<>0)) and
    [Row] = 1
GROUP BY GFCUS, Ne.NEEAN, SCDLE, SAPOD, SATCD,
    CUS.GFCUN, BGCFN1, BGCFN2, BGCFN3, SV.SVCSA, 
     SV.SVNA1, SV.SVNA2, SV.SVNA3, SV.SVNA4, SV.SVNA5, SV.SVPZIP, SV.NONUK
ORDER BY MAX(SCAN) ASC

如果您不想返回[Row]列，可以将其封装在子查询中。

Answer 2

您可以使用row_number获得每位客户的前1行

在where子句中需要返回pos值为1的值

示例查询

row_number() over ( partition by GFCUS order by SAPOD desc) as pos