Question

我使用POSIX timerfd函数创建了一个计时器。意图是，计时器应该是周期性的，并且从名为myFunc( )的单独函数中观察计时器到期

我多次调用此函数，以便在等待5秒后定期查看定时器到期时间。

问题是，一旦它第一次在5秒后到期，下次再过......它不会再次到期，即从第二次迭代开始没有观察到5秒的延迟。

有人能告诉我我错过了什么吗？

#include <stdio.h>
#include <iostream>
#include <errno.h>
#include <dlfcn.h>
#include <assert.h>
#include <sys/mman.h>
#include <new>

#include <limits.h>
#include <sys/epoll.h>
#include <sys/timerfd.h>

using namespace std;

struct epoll_event event;
int timer_fd, efd, no_of_fd;
void myFunc( int i );

int main()
{
  struct itimerspec its;

  its.it_value.tv_sec = 5;
  its.it_value.tv_nsec = 0;

  its.it_interval.tv_sec = 3; // Every 3 seconds interval
  its.it_interval.tv_nsec = 0;


  efd = epoll_create(2);
  timer_fd = timerfd_create(CLOCK_REALTIME, TFD_NONBLOCK);

  if ( timer_fd == -1 )
  {
    fprintf(stderr, "timerfd_create error in start timer");
    return 1;
  }

  event.data.fd = timer_fd;
  event.events = EPOLLIN|EPOLLPRI;

  if ( epoll_ctl(efd, EPOLL_CTL_ADD, timer_fd, &event) == -1 )
  {
     fprintf(stderr, "epoll_ctl error in start timer"); 
     return 1;
  }

  if ( timerfd_settime(timer_fd, 0, &its, NULL) == -1 )
  {
    fprintf(stderr, "timerfd_settime error in start timer");
    return 1;
  }
  myFunc( 10 );
  myFunc( 20 );
  myFunc( 30 );
}

void myFunc( int i )
{
  printf("Inside myFunc %d\n", i);
  no_of_fd = 0;
  struct epoll_event revent;
  errno = 0;
  do {
     no_of_fd = epoll_wait(efd, &revent, 1, -1);
  } while ( no_of_fd < 0 && errno == EINTR );

  if ( no_of_fd < 0 )
  {
    fprintf(stderr, "epoll_wait error in start timer");

  }

  if ( revent.data.fd == timer_fd ) {
     printf("Timer expired \n");    
  }

}

Answer 1

将epoll与电平触发一起使用时，应在每个EPOLLIN上读取8个字节。这是一个int64，它告诉您事件过期的次数。有效地阅读＆＃34;清除＆＃34;这个数字使得下一个EPOLLIN是不同事件到期的结果。

手册告诉你阅读：

          If the timer has already expired one or more times since its
          settings were last modified using timerfd_settime(), or since
          the last successful read(2), then the buffer given to read(2)
          returns an unsigned 8-byte integer (uint64_t) containing the
          number of expirations that have occurred.  (The returned value
          is in host byte order—that is, the native byte order for
          integers on the host machine.)

为什么我的计时器不是定期的，而是只过了一次？

1 个答案: