使用Mockito,我如何匹配地图的键值对?

时间:2010-04-05 18:52:56

标签: java mockito

我需要根据特定的键值从模拟对象发送一个特定的值。

来自具体课程:

map.put("xpath", "PRICE");
search(map);

从测试用例:

IOurXMLDocument mock = mock(IOurXMLDocument.class);
when(mock.search(.....need help here).thenReturn("$100.00");

如何为此键值对模拟此方法调用?

5 个答案:

答案 0 :(得分:17)

我发现这试图解决类似的问题,创建一个带有Map参数的Mockito存根。我不想为有问题的地图编写自定义匹配器,然后我找到了一个更优雅的解决方案:使用hamcrest-library中的其他匹配器与mockito' s argThat:

when(mock.search(argThat(hasEntry("xpath", "PRICE"))).thenReturn("$100.00");

如果你需要检查多个条目,那么你可以使用其他的hamcrest好东西:

when(mock.search(argThat(allOf(hasEntry("xpath", "PRICE"), hasEntry("otherKey", "otherValue")))).thenReturn("$100.00");

这开始变得很长,非平凡的地图,所以我最终提取方法来收集条目匹配器并将它们粘贴在我们的TestUtils中:

import static org.hamcrest.Matchers.allOf;
import static org.hamcrest.Matchers.anyOf;
import static org.hamcrest.Matchers.hasEntry;

import java.util.ArrayList;
import java.util.List;
import java.util.Map;

import org.hamcrest.Matcher;
---------------------------------
public static <K, V> Matcher<Map<K, V>> matchesEntriesIn(Map<K, V> map) {
    return allOf(buildMatcherArray(map));
}

public static <K, V> Matcher<Map<K, V>> matchesAnyEntryIn(Map<K, V> map) {
    return anyOf(buildMatcherArray(map));
}

@SuppressWarnings("unchecked")
private static <K, V> Matcher<Map<? extends K, ? extends V>>[] buildMatcherArray(Map<K, V> map) {
    List<Matcher<Map<? extends K, ? extends V>>> entries = new ArrayList<Matcher<Map<? extends K, ? extends V>>>();
    for (K key : map.keySet()) {
        entries.add(hasEntry(key, map.get(key)));
    }
    return entries.toArray(new Matcher[entries.size()]);
}

所以我离开了:

when(mock.search(argThat(matchesEntriesIn(map))).thenReturn("$100.00");
when(mock.search(argThat(matchesAnyEntryIn(map))).thenReturn("$100.00");

有一些与泛型相关的丑陋,我压制了一个警告,但至少它干了并隐藏在TestUtil中。

最后一点,请注意embedded hamcrest issues in JUnit 4.10。对于Maven,我建议首先导入hamcrest-library然后再导入JUnit 4.11(现在是4.12)并从JUnit中排除hamcrest-core只是为了测量:

<dependency>
    <groupId>org.hamcrest</groupId>
    <artifactId>hamcrest-library</artifactId>
    <version>1.3</version>
    <scope>test</scope>
</dependency>
<dependency>
    <groupId>junit</groupId>
    <artifactId>junit</artifactId>
    <version>4.12</version>
    <scope>test</scope>
    <exclusions>
        <exclusion>
            <groupId>org.hamcrest</groupId>
            <artifactId>hamcrest-core</artifactId>
        </exclusion>
    </exclusions>
</dependency>
<dependency>
    <groupId>org.mockito</groupId>
    <artifactId>mockito-all</artifactId>
    <version>1.9.5</version>
    <scope>test</scope>
</dependency>

编辑:2017年9月1日 - 根据一些评论,我更新了我的答案,以显示我的Mockito依赖关系,我在test util中的导入,以及截至今天运行绿色的junit:

import static blah.tool.testutil.TestUtil.matchesAnyEntryIn;
import static blah.tool.testutil.TestUtil.matchesEntriesIn;
import static org.hamcrest.MatcherAssert.assertThat;
import static org.hamcrest.Matchers.is;
import static org.mockito.Matchers.argThat;
import static org.mockito.Mockito.mock;
import static org.mockito.Mockito.when;

import java.util.HashMap;
import java.util.Map;

import org.junit.Test;

public class TestUtilTest {

    @Test
    public void test() {
        Map<Integer, String> expected = new HashMap<Integer, String>();
        expected.put(1, "One");
        expected.put(3, "Three");

        Map<Integer, String> actual = new HashMap<Integer, String>();
        actual.put(1, "One");
        actual.put(2, "Two");

        assertThat(actual, matchesAnyEntryIn(expected));

        expected.remove(3);
        expected.put(2, "Two");
        assertThat(actual, matchesEntriesIn(expected));
    }

    @Test
    public void mockitoTest() {
        SystemUnderTest sut = mock(SystemUnderTest.class);
        Map<Integer, String> expected = new HashMap<Integer, String>();
        expected.put(1, "One");
        expected.put(3, "Three");

        Map<Integer, String> actual = new HashMap<Integer, String>();
        actual.put(1, "One");

        when(sut.search(argThat(matchesAnyEntryIn(expected)))).thenReturn("Response");
        assertThat(sut.search(actual), is("Response"));
    }

    protected class SystemUnderTest {
        // We don't really care what this does
        public String search(Map<Integer, String> map) {
            if (map == null) return null;
            return map.get(0);
        }
    }
}

答案 1 :(得分:7)

如果您只想与特定地图“匹配”,您可以使用上面的一些答案,或者使用扩展Map的自定义“匹配器”或ArgumentCaptor,如下所示:

ArgumentCaptor<Map> argumentsCaptured = ArgumentCaptor.forClass(Map.class);
verify(mock, times(1)).method((Map<String, String>) argumentsCaptured.capture());
assert argumentsCaptured.getValue().containsKey("keyname"); 
// .getValue() will be the Map it called it with.

另请参阅此处的更多答案:Verify object attribute value with mockito

答案 2 :(得分:3)

这不起作用吗?

Map<String, String> map = new HashMap<String, String>();
map.put("xpath", "PRICE");
when(mock.search(map)).thenReturn("$100.00");

Map参数的行为应与其他参数相同。

答案 3 :(得分:2)

看起来像你需要的是Answer

IOurXMLDocument doc = mock(IOurXMLDocument.class);
when(doc.search(Matchers.<Map<String,String>>any())).thenAnswer(new Answer<String>() {
    @Override
    public String answer(InvocationOnMock invocation) throws Throwable {
        Map<String, String> map = (Map<String, String>) invocation.getArguments()[0];
        String value = map.get("xpath");
        if ("PRICE".equals(value)) {
            return "$100.00";
        } else if ("PRODUCTNAME".equals(value)) {
            return "Candybar";
        } else {
            return null;
        }
    }
});

但似乎更好的想法是不使用原始Map作为搜索方法的参数 - 您可以将此地图转换为具有priceproductName属性的pojo。只是一个想法:)

答案 4 :(得分:0)

晚参加聚​​会 11 年,但 org.mockito.Matchers#anyMapOf 为我工作。在 OP 的示例中,它将是:

when(mock.search(anyMapOf(String.class, String.class))).thenReturn("$100.00");