Question

我遇到了执行嵌套的foreach循环执行以获得所需结果的问题。以下是场景：

以下是两个数组的结果

结果1：

Array ( [0]=> Array ( [questionID] => 103 [answer] => Female [answer_cnt] => 8 ) 
       [1] => Array ( [questionID] => 103 [answer] => Male [answer_cnt] => 9 )
      )

结果2

Array ( [0] => Male [1] => Female )

我使用foreach循环的代码在

之下

 foreach($qrs as $qrow)

        {       foreach($d as $q){

                    echo"<br>".$q;                                                              
                  echo $qrow['answer_cnt']."<br>";}
        }

它将获得输出：

Male 8

Female8

Male 9

Female9

但我的预期输出是

 Female 8

 Male 9

Answer 1

你不需要循环第二个。只需使用第一个。

foreach($qrs as $qrow) {
    echo $qrow['answer'] . ' ' . $qrow['answer_cnt'] . '<br/>';
}

目前还不清楚为什么你需要第二个数组，但是如果你想要包含它（没有意义），只需要包含一个if。

foreach($qrs as $qrow) {
    foreach($d as $q) {
        if($qrow['answer'] == $q) {
            echo $qrow['answer'] . ' ' . $qrow['answer_cnt'] . '<br/>';
        }
    }
}

Answer 2

你的第二个阵列没用。只是做：

foreach($qrs as $qrow)
    {      
              echo"<br>".$qrow['answer']." ";                                                              
              echo $qrow['answer_cnt']."<br>";}
    }

Answer 3

使用此...

 foreach($qrs as $qrow)
        {   
            foreach($d as $q)
            {
                if(in_array($q, $qrow))
                {
                    echo"<br>".$q;                                                              
                    echo $qrow['answer_cnt']."<br>";    
                }
            }
        }

Answer 4

$arr = array(
    array( 'questionID' => 103, 'answer' => 'Female',  'answer_cnt' => 8),
    array( 'questionID' => 103, 'answer' => 'Male',  'answer_cnt' => 9)
);

if(count($arr) > 0) {
    foreach($arr as $val) {
        echo "$val[answer] $val[answer_cnt] <br />";
    }
}

你也可以试试这个。

嵌套的foreach循环执行？

4 个答案: