Question

我有一个问题，我必须在Python（v3.4.1）中计算重复的单词并将它们放在一个句子中。我使用了计数器，但我不知道如何按以下顺序获取输出。输入是：

mysentence = As far as the laws of mathematics refer to reality they are not certain as far as they are certain they do not refer to reality

我把它变成了一个列表并对其进行了排序

输出结果为

"As" is repeated 1 time.
"are" is repeated 2 times.
"as" is repeated 3 times.
"certain" is repeated 2 times.
"do" is repeated 1 time.
"far" is repeated 2 times.
"laws" is repeated 1 time.
"mathematics" is repeated 1 time.
"not" is repeated 2 times.
"of" is repeated 1 time.
"reality" is repeated 2 times.
"refer" is repeated 2 times.
"the" is repeated 1 time.
"they" is repeated 3 times.
"to" is repeated 2 times.

到目前为止，我已经到了这一步

x=input ('Enter your sentence :')
y=x.split()
y.sort()
for y in sorted(y):
    print (y)

Answer 1

我可以看到你在哪里排序，因为你可以可靠地知道你什么时候打了一个新单词并跟踪每个独特单词的计数。但是，您真正想要做的是使用哈希（字典）来跟踪计数，因为字典键是唯一的。例如：

words = sentence.split()
counts = {}
for word in words:
    if word not in counts:
        counts[word] = 0
    counts[word] += 1

现在，它将为您提供一个字典，其中键是单词，值是它出现的次数。您可以使用collections.defaultdict(int)进行操作，因此您只需添加值：

counts = collections.defaultdict(int)
for word in words:
    counts[word] += 1

但是甚至还有更好的东西...... collections.Counter会将你的单词列表转换成包含计数的字典（实际上是字典的扩展名）。

counts = collections.Counter(words)

从那里你想要排序顺序的单词列表及其计数，以便你可以打印它们。 items()将为您提供元组列表，sorted将按每个元组的第一项（本例中的单词）排序（默认情况下）......这正是您想要的。< / p>

import collections
sentence = """As far as the laws of mathematics refer to reality they are not certain as far as they are certain they do not refer to reality"""
words = sentence.split()
word_counts = collections.Counter(words)
for word, count in sorted(word_counts.items()):
    print('"%s" is repeated %d time%s.' % (word, count, "s" if count > 1 else ""))

输出

"As" is repeated 1 time.
"are" is repeated 2 times.
"as" is repeated 3 times.
"certain" is repeated 2 times.
"do" is repeated 1 time.
"far" is repeated 2 times.
"laws" is repeated 1 time.
"mathematics" is repeated 1 time.
"not" is repeated 2 times.
"of" is repeated 1 time.
"reality" is repeated 2 times.
"refer" is repeated 2 times.
"the" is repeated 1 time.
"they" is repeated 3 times.
"to" is repeated 2 times.

Answer 2

以排序顺序打印字符串中的单词重复：

from itertools import groupby 

mysentence = ("As far as the laws of mathematics refer to reality "
              "they are not certain as far as they are certain "
              "they do not refer to reality")
words = mysentence.split() # get a list of whitespace-separated words
for word, duplicates in groupby(sorted(words)): # sort and group duplicates
    count = len(list(duplicates)) # count how many times the word occurs
    print('"{word}" is repeated {count} time{s}'.format(
            word=word, count=count,  s='s'*(count > 1)))

Output

"As" is repeated 1 time
"are" is repeated 2 times
"as" is repeated 3 times
"certain" is repeated 2 times
"do" is repeated 1 time
"far" is repeated 2 times
"laws" is repeated 1 time
"mathematics" is repeated 1 time
"not" is repeated 2 times
"of" is repeated 1 time
"reality" is repeated 2 times
"refer" is repeated 2 times
"the" is repeated 1 time
"they" is repeated 3 times
"to" is repeated 2 times

Answer 3

嘿，我已经在python 2.7（mac）上试过了，因为我有那个版本所以试着掌握逻辑

from collections import Counter

mysentence = """As far as the laws of mathematics refer to reality they are not certain as far as they are certain they do not refer to reality"""

mysentence = dict(Counter(mysentence.split()))
for i in sorted(mysentence.keys()):
    print ('"'+i+'" is repeated '+str(mysentence[i])+' time.')

我希望这就是你正在寻找的东西，如果没有那么请我高兴地学习新东西。

"As" is repeated 1 time.
"are" is repeated 2 time.
"as" is repeated 3 time.
"certain" is repeated 2 time.
"do" is repeated 1 time.
"far" is repeated 2 time.
"laws" is repeated 1 time.
"mathematics" is repeated 1 time.
"not" is repeated 2 time.
"of" is repeated 1 time.
"reality" is repeated 2 time.
"refer" is repeated 2 time.
"the" is repeated 1 time.
"they" is repeated 3 time.
"to" is repeated 2 time.

Answer 4

这是一个非常糟糕的例子，不使用除列表之外的其他任何内容：

x = "As far as the laws of mathematics refer to reality they are not certain as far as they are certain they do not refer to reality"
words = x.split(" ")
words.sort()

words_copied = x.split(" ")
words_copied.sort()

for word in words:
    count = 0
    while(True):
        try:
            index = words_copied.index(word)
            count += 1
            del words_copied[index]
        except ValueError:
            if count is not 0:
                print(word + " is repeated " + str(count) + " times.")
            break

编辑：这是一个更好的方法：

x = "As far as the laws of mathematics refer to reality they are not certain as far as they are certain they do not refer to reality"
words = x.split(" ")
words.sort()

last_word = ""
for word in words:
    if word != last_word:
        count = [i for i, w in enumerate(words) if w == word]
        print(word + " is repeated " + str(len(count)) + " times.")
    last_word = word

Python重复的单词

4 个答案:

Output