Question

在此

Document document = documentBuilder.parse(filename);

我试图通过buffered input stream读取一组Xml文件。当我在命令提示符下输入文件时，我收到错误As System Cannot find the specified File。有人可以建议如何从这里继续

import java.io.File;
import java.io.*;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NamedNodeMap;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;

public class XMLFile {

    public static void main(String argv[]) {
        try {

            DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory
                    .newInstance();
            DocumentBuilder documentBuilder = documentBuilderFactory
                    .newDocumentBuilder();
            BufferedReader bufferRead = new BufferedReader(
                    new InputStreamReader(System.in));
            String s = bufferRead.readLine();
            File dir = new File(s);
            String[] children = dir.list();
            if (children == null) {
            } else {
                for (int i = 0; i < children.length; i++) {
                    String filename = children[i];
                    Document document = documentBuilder.parse(filename);
                    System.out.println(filename);
                    NodeList employees = document
                            .getElementsByTagName("connection");
                    for (int q = 0; q < employees.getLength(); q++) {
                        System.out.println(employees.getLength());
                        Node employee = employees.item(q);
                        NamedNodeMap attribute = employee.getAttributes();
                        Node nodeAttr = attribute.getNamedItem("server");
                        nodeAttr.setTextContent("aventador.am.lilly.com:1530");
                        Node nodeAttr1 = attribute.getNamedItem("service");
                        Node nodeAttr2 = attribute.getNamedItem("port");
                        nodeAttr1.setTextContent("tst806");
                        nodeAttr2.setTextContent("");

                    }
                    System.out.println(filename);
                    TransformerFactory transformerFactory = TransformerFactory
                            .newInstance();
                    Transformer transformer = transformerFactory
                            .newTransformer();
                    DOMSource domSource = new DOMSource(document);
                    StreamResult streamResult = new StreamResult(new File(
                            filename));
                    transformer.transform(domSource, streamResult);
                    System.out.println("The XML File was ");
                }
            }

        } catch (ParserConfigurationException pce) {
            pce.printStackTrace();
        } catch (TransformerException tfe) {
            tfe.printStackTrace();
        } catch (IOException ioe) {
            ioe.printStackTrace();
        } catch (SAXException sae) {
            sae.printStackTrace();
        } catch (Exception sae1) {
            sae1.printStackTrace();
        }
    }
}

Answer 1

在您的其他区域内，您正尝试Document document = documentBuilder.parse(filename);

filename参数应该是URI - 意思是完整的文件路径。但是您只传递文件名，因此无论您的输入目录如何，DocumentBuilder都会查看XML文件的当前目录。更改以下行

String filename = children[i];

到

String filename = dir.getAbsolutePath() + File.separator + children[i];

这应解决问题。

系统找不到FIle指定的文档document = documentBuilder（）

1 个答案: