Question

public class numPattern {
    public static void main(String[] args) {
        int digit1 = 2;
        int digit2 = 7;
        int    tal = 0;

        System.out.print(digit1 + " ");
        System.out.print(digit2 + " ");

        while (tal < 550) {
            tal = digit1 + digit2;

            System.out.print(tal + " ");

            digit1 = digit2;
            digit2 = tal;
        }
    }
}

这会输出2, 7, 9, 16, 25, 41, 66......453 and 733

问题是它应该停在453，因为733超过了550。

什么命令可以确保程序在453处结束以满足大于或等于550我试图寻找？

Answer 1

在tal：

中增加while的值

    int digit1 = 2;
    int digit2 = 7;
    int tal = 0;

    System.out.print(digit1 + " ");
    System.out.print(digit2 + " ");

    while((tal = digit1 + digit2)< 550)
    {

        System.out.print(tal + " ");

        digit1 = digit2;
        digit2 = tal;
    }

Answer 2

只需跳过digit2的打印输出，将tal初始化为相同的值，然后对循环中的语句重新排序：

int digit1 = 2;
System.out.print(digit1 + " ");

int digit2 = 7;
int tal = digit2;
while (tal < 550) {
    System.out.print(tal + " ");
    tal = digit1 + digit2;
    digit1 = digit2;
    digit2 = tal;
}

Answer 3

简单的改变：

while (tal < 550){
    tal = digit1 + digit2;

    System.out.print(tal + " ");
    digit1 = digit2;
    digit2 = tal;
}

为：

while (tal < 550) {
    System.out.print(tal + " ");

    digit1 = digit2;
    digit2 = tal;
    tal = digit1 + digit2;
}

和tal的初始化：
从int tal = 0到int tal = digit1 + digit2;

Answer 4

 int digit1 = 2;

 System.out.print(digit1 + " "); //it will print digit1
do not print digit2

int digit2 = 7;
int tal = digit2;
while (tal < 550) {
    System.out.print(tal + " ");
    tal = digit1 + digit2;
    digit1 = digit2;
    digit2 = tal;
}

因为在循环中它首先增加值然后打印它，所以在条件为false之前它已经打印了tal = 443时的值然后它进入while循环执行总和并打印它然后去检查值

重新调整后，首先打印出值，然后执行总和，检查其是否较少，因此在443之后不会继续

数字模式截止

4 个答案: