Question

所以我一直在寻找能够在两个日期之间获得时间跨度的函数，并且我已经在SO上找到了这个答案

但是，日期格式为7/Nov/2012 20:30:00，日期为7/11/2012 20:30:00，我的值来自输入

如果试图改变＆＃34; Nov＆＃34;至＆＃34; 11＆＃34;我输出了NaN。我必须转换日期吗？

这是代码。

<!DOCTYPE html>
<html>
<head>
<meta charset=utf-8 />
</head>
<body>
  <input type="text" id ="start"value="7/Nov/2012 20:30:00" />

  <input type="text" id="end" value="20/Nov/2012 19:15:00" />
</body>
</html>

javascript

var startDate = document.getElementById("start").value;
var endDate = document.getElementById("end").value;

var date1 = new Date(startDate);
var date2 = new Date(endDate);

var diff = date2.getTime() - date1.getTime();

var days = Math.floor(diff / (1000 * 60 * 60 * 24));
diff -=  days * (1000 * 60 * 60 * 24);

var hours = Math.floor(diff / (1000 * 60 * 60));
diff -= hours * (1000 * 60 * 60);

var mins = Math.floor(diff / (1000 * 60));
diff -= mins * (1000 * 60);

var seconds = Math.floor(diff / (1000));
diff -= seconds * (1000);


console.log(days + " days : " + hours + " hours : " + mins + " minutes : " + seconds + " seconds");

Answer 1

使用您的20/11/2012 20:30:00日期格式：

var startDate = "7/11/2012 20:30:00";
var endDate = "20/11/2012 19:15:00";

您正在获取NaN，因为它需要格式为mm / dd / yyyy。所以20当然是一个无效的月份..交换月份和日期值，如：

var parts = startDate.split('/');
startDate = parts[1] + '/' + parts[0] + '/' + parts[2];
// 11/7/2012 20:30:00

var parts = endDate.split('/');
endDate = parts[1] + '/' + parts[0] + '/' + parts[2];
// 11/20/2012 9:15:00

然后做正常的时间差异工作，它会起作用：

var date1 = new Date(startDate);
var date2 = new Date(endDate);



var diff = date2.getTime() - date1.getTime();

var days = Math.floor(diff / (1000 * 60 * 60 * 24));
diff -=  days * (1000 * 60 * 60 * 24);

var hours = Math.floor(diff / (1000 * 60 * 60));
diff -= hours * (1000 * 60 * 60);

var mins = Math.floor(diff / (1000 * 60));
diff -= mins * (1000 * 60);

var seconds = Math.floor(diff / (1000));
diff -= seconds * (1000);

alert(days + " days : " + hours + " hours : " + mins + " minutes : " + seconds + " seconds");
//12 days 22 hours 45 minutes 0 seconds

<强> See the DEMO here

Answer 2

使用JavaScript Date并只需调用new Date("7/Nov/2012 20:30:00")即可获取JS Date对象。然后，您可以使用该Date对象上的方法提取日，月和年。

Timespan javascript

2 个答案: