Question

我需要什么：

我面临的问题不是键值对中的数据。

这是我的代码

$元数据= json_decode（$元数据，TRUE）;

它输出我的数组

  Array
 (
   [name] => Yogender
   [email] => yogensingh@
    [designation] => Business Manager
    [website] => 
    [phone] => 91-92
    [company] => Veer Signages Pvt. Ltd.
    [city] => Gurgaon
[country] => India
 )
 Array
(
[name] => Prakash Tiwari
[email] => digital
[designation] => Director
[website] => 
[phone] => 91-981
[company] => Digital Semiconductors Pvt. Ltd
[city] => New Delhi
[country] => India
  )

使用foreach循环获取此数组

foreach($metadata as $key=>$value)

{
  echo  $value['name'];

}

输出第一个数组
```
 output    yB9VGI

     PdD9DNI
```
我只想取[＆＃39;指定＆＃39;]＆amp;密钥值对中的[＆＃39; company＆＃39;]。喜欢
```
 [designation] => manager
  [company]=>google
```
请告诉我哪里有错误，欢迎提出任何建议。

Answer 1

这就是你要找的东西：

foreach($metadata as $key => $value) {
 if ($key === 'designation' || $key === 'company')
  echo  $value;
}

Answer 2

试试这个

foreach($metadata as $value)

{
  echo  $value->name;

}

Answer 3

试

foreach($arr as $k=>$v) {
  if($k == 'designation' || $k == 'company')
    $newarr[][$k] = $v;
}
print_r($newarr);

Answer 4

最后我做到了这一点它工作正常如下

 foreach($metadata as $key => $value) 
  {
    if ($key == 'designation' )
       $designation= $value;
    elseif($key == 'company')
         $company= $value;

}

echo“D = $ names and C = $ company \ n”;

因为每个循环都不适用于PHP

4 个答案: