Question

在数据库表中我有一个realpath - details.html？cat_id = 48＆amp; id = 295，在表2中 - 有id 295.我可以从表1中选择单元格，其中id在url = id表2中吗？我这样做，但它不起作用：

$sql = one.realpath, two.id FROM one, two WHERE one.realpath REGEXP '[0-9]+$' = two.id

Answer 1

编辑 - 如你所说，数字不应该是静态的 -

你可以试试这个 -

$myNumber = 295; // If you want to define it in a variable and then use if

或试试这个 -

$myNumber = myCheckingFunction(); // If the value is returned from a function

或试试这个 -

$myNumber = $someRowFromDB['field_name']; // If you are trying to fetch it from a db row

然后你可以把它替换成这样的代码 -

$searchNeedle = 'id=' . $myNumber;
$query = "select * from tablename where two.realpath like '%$searchNeedle'";

Answer 2

如果您的表格如下：

select * from one;

+-------------------------------+
| realpath                      |
+-------------------------------+
| details.html?cat_id=48&id=295 |
| details.html?cat_id=48&id=234 |
+-------------------------------+

如果你在sql console中执行expresion：

SELECT one.realpath REGEXP '[0-9]+$' TEST FROM one

此查询返回

+------+
| TEST |
+------+
|    1 |
|    1 |
+------+

出于这个原因，当你尝试

时

WHERE one.realpath REGEXP '[0-9]+$' = two.id

你在做：

WHERE '1' = two.id

您可以尝试此查询。它可能会更好，但它正在发挥作用：

SELECT one.realpath, two.id FROM one
INNER JOIN two ON (one.realpath REGEXP CONCAT('id=',two.id, '$'))

结果如下：

+-------------------------------+-----+
| realpath                      | id  |
+-------------------------------+-----+
| details.html?cat_id=48&id=295 | 295 |
+-------------------------------+-----+

添加'id ='很重要，因为如果你不添加它，你可能会得到这样的结果：

SELECT one.realpath, two.id FROM one
INNER JOIN two ON (one.realpath REGEXP CONCAT(two.id, '$'))

+-------------------------------+----+
| realpath                      | id |
+-------------------------------+----+
| details.html?cat_id=48&id=295 |  5 |
+-------------------------------+----+

使用regexp从DB查询

2 个答案: