我正在使用此链接:
private static final String PLACES_SEARCH_URL = "htt`ps://maps.googleapis.com/maps/api/place/search/json?";`
搜索地点,一切正常。
我已从console.developers.google.com/project/
生成服务器密钥但是当我签署我的申请时,我无法获得这些地方。
是因为我的申请名称?
GoogleHeaders headers = new GoogleHeaders();
headers.setApplicationName("**myApplicationName**");
我应该把它放在这里?
这是示例代码:
public class GooglePlaces {
/** Global instance of the HTTP transport. */
private static final HttpTransport HTTP_TRANSPORT = new NetHttpTransport();
// Google API Key
private static final String API_KEY = "MY SERVER API KEY";
// Google Places serach url's
private static final String PLACES_SEARCH_URL = "https://maps.googleapis.com/maps/api/place/search/json?";
//private static final String PLACES_TEXT_SEARCH_URL = "https://maps.googleapis.com/maps/api/place/search/json?";
private static final String PLACES_DETAILS_URL = "https://maps.googleapis.com/maps/api/place/details/json?";
private double _latitude;
private double _longitude;
private double _radius;
/**
* Searching places
* @param latitude - latitude of place
* @params longitude - longitude of place
* @param radius - radius of searchable area
* @param types - type of place to search
* @return list of places
* */
public PlacesList search(double latitude, double longitude, double radius, String types)
throws Exception {
this._latitude = latitude;
this._longitude = longitude;
this._radius = radius;
try {
HttpRequestFactory httpRequestFactory = createRequestFactory(HTTP_TRANSPORT);
HttpRequest request = httpRequestFactory
.buildGetRequest(new GenericUrl(PLACES_SEARCH_URL));
request.getUrl().put("key", API_KEY);
request.getUrl().put("location", _latitude + "," + _longitude);
request.getUrl().put("radius", _radius); // in meters
request.getUrl().put("sensor", "false");
if(types != null)
request.getUrl().put("types", types);
PlacesList list = request.execute().parseAs(PlacesList.class);
// Check log cat for places response status
Log.d("Places Status", "" + list.status);
return list;
} catch (HttpResponseException e) {
Log.e("Error:", e.getMessage());
return null;
}
}
/**
* Searching single place full details
* @param refrence - reference id of place
* - which you will get in search api request
* */
public PlaceDetails getPlaceDetails(String reference) throws Exception {
try {
HttpRequestFactory httpRequestFactory = createRequestFactory(HTTP_TRANSPORT);
HttpRequest request = httpRequestFactory
.buildGetRequest(new GenericUrl(PLACES_DETAILS_URL));
request.getUrl().put("key", API_KEY);
request.getUrl().put("reference", reference);
request.getUrl().put("sensor", "false");
PlaceDetails place = request.execute().parseAs(PlaceDetails.class);
return place;
} catch (HttpResponseException e) {
Log.e("Error in Perform Details", e.getMessage());
throw e;
}
}
/**
* Creating http request Factory
* */
public static HttpRequestFactory createRequestFactory(
final HttpTransport transport) {
return transport.createRequestFactory(new HttpRequestInitializer() {
public void initialize(HttpRequest request) {
GoogleHeaders headers = new GoogleHeaders();
headers.setApplicationName("MyAppName");
request.setHeaders(headers);
JsonHttpParser parser = new JsonHttpParser(new JacksonFactory());
request.addParser(parser);
}
});
}
}
答案 0 :(得分:0)
你应该在android应用程序中链接google place api: -
这将有助于您获得地图v2。
答案 1 :(得分:0)
使用google map API保留Serializable类后解决了这个问题
-keepnames class * implements java.io.Serializable
-keepclassmembers class * implements java.io.Serializable {
static final long serialVersionUID;
private static final java.io.ObjectStreamField[] serialPersistentFields;
!static !transient <fields>;
!private <fields>;
!private <methods>;
private void writeObject(java.io.ObjectOutputStream);
private void readObject(java.io.ObjectInputStream);
java.lang.Object writeReplace();
java.lang.Object readResolve();
}