从EditText输入和打印

时间:2014-09-11 04:14:06

标签: java android

所以我试图从EditText视图中获取一个字符串并存储到一个变量中,然后在单击CreateBtn时打印该变量。不能让这个工作。我认为,由于CreateBtn而继续崩溃,我认为它可能与AlertBox有关,这是EditText视图所在的位置。

public class MyActivity extends Activity {


// declares vars
final Context context = this;
private Button addClassBtn;
private Button createBtn;
public EditText classNameInput;
private String classTextName;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_my);

    // initializes var
    final LayoutInflater classInfo = getLayoutInflater();
    addClassBtn = (Button) findViewById(R.id.classBtn);
    classNameInput = (EditText) findViewById(R.id.classNameInput);
    createBtn = (Button) findViewById(R.id.createBtn);

    // creates a alert box with a text view when button is clicked
    addClassBtn.setOnClickListener(
        new View.OnClickListener() {
        @Override
        public void onClick(View view) {

            AlertDialog.Builder builder = new AlertDialog.Builder(context);

            builder.setView(classInfo.inflate(R.layout.class_info, null));

            builder.setTitle("Add Class");

            AlertDialog diaBox = builder.create();

            diaBox.show();

        }
    });

    //classNameInput is extracted to a variable
    createBtn.setOnClickListener(
            new View.OnClickListener() {
                @Override
                public void onClick(View view) {
                    String className;

                    className = classNameInput.getText().toString();

                    Log.v("EditText", className);

                }
            });

这是class_info.xml

<?xml version="1.0" encoding="utf-8"?>

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="wrap_content"
android:layout_height="wrap_content">

<EditText
    android:id="@+id/classNameInput"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:layout_marginTop="20dp"
    android:layout_marginBottom="20dp"
    android:paddingTop="25dp"
    android:hint="    class name    "
    android:textSize="25sp"
    android:paddingBottom="20dp"
    android:fontFamily="monospace"
    android:inputType="textAutoComplete|textAutoCorrect"
    android:textAlignment="center"
    android:paddingLeft="-10dp"
    android:paddingRight="-10dp" />

<Button
    android:layout_alignParentStart="true"
    android:layout_alignParentLeft="true"
    android:layout_below="@+id/classNameInput"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:id="@+id/createBtn"
    android:fontFamily="monospace"
    android:textSize="23sp"
    android:text="create"
    android:onClick="createBtnClick" />

</RelativeLayout>

这是activity_my.xml

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
android:paddingBottom="@dimen/activity_vertical_margin"
tools:context=".MyActivity">

<Button
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:text="+"
    android:id="@+id/classBtn"
    android:clickable="false"
    android:textSize="100sp"
    android:layout_centerVertical="true"
    android:layout_centerHorizontal="true"
    android:onClick="onClassBtnClick"
    android:paddingLeft="50dp"
    android:paddingRight="50dp"
    android:paddingTop="10dp"
    android:paddingBottom="10dp"
    android:focusable="true" />

 </RelativeLayout>

1 个答案:

答案 0 :(得分:0)

我认为当你按下createBtn时会出现NullPointerException,因为当你尝试在createBtn的OnClickListener中使用它时,classNameInput为null。

语句“(EditText) findViewById(R.id.classNameInput)”始终返回null,因为您的EditText位于AlterDialog中,当您使用该语句时,该语法尚未创建。

为了解决您的问题,我需要知道您的createBtn在哪里。如果你发布你的activity_my xml和class_info xml,那就更好了。

<强>更新

根据您发布的布局文件,我知道您在启动MyActivity时会立即获得NullPointerException,因为当您为其设置OnClickListener时,您的createBtn为null。原因与我对你的classNameInput的说法相同。

我更改了部分代码以解决您的问题。以下代码应该可以解决您的问题:

public class MyActivity extends Activity {


// declares vars
final Context context = this;
private Button addClassBtn;
private Button createBtn;
public EditText classNameInput;
private String classTextName;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_my);
       // initializes var
    final LayoutInflater classInfo = getLayoutInflater();
    addClassBtn = (Button) findViewById(R.id.classBtn);

    // creates a alert box with a text view when button is clicked
    addClassBtn.setOnClickListener(
        new View.OnClickListener() {
        @Override
        public void onClick(View view) {

            AlertDialog.Builder builder = new AlertDialog.Builder(context);

            View dialogView = classInfo.inflate(R.layout.class_info, null);

            setDialogViews(dialogView);

            builder.setView(dialogView);

            builder.setTitle("Add Class");

            AlertDialog diaBox = builder.create();

            diaBox.show();

        }
    });


    private void setDialogViews(View dialogView){
        classNameInput = (EditText) dialogView.findViewById(R.id.classNameInput);
        createBtn = (Button) dialogView.findViewById(R.id.createBtn);

        //classNameInput is extracted to a variable
        createBtn.setOnClickListener(
                new View.OnClickListener() {
                    @Override
                    public void onClick(View view) {
                        String className;

                        className = classNameInput.getText().toString();

                        Log.v("EditText", className);

                    }
                });
    }