我目前正在使用此C代码:
CURL *curl;
CURLcode res;
curl = curl_easy_init();
if (curl) {
curl_easy_setopt(curl, CURLOPT_URL, "http://my-domain.org/");
res = curl_easy_perform(curl);
curl_easy_cleanup(curl);
}
它在控制台上打印输出。我怎样才能得到相同的输出,但是把它读成一个字符串? (这可能是一个基本问题,但我还不了解libcurl API ...)
感谢您的帮助!
麦克
答案 0 :(得分:16)
您需要传递函数和缓冲区以将其写入缓冲区。
/* setting a callback function to return the data */
curl_easy_setopt(curl_handle, CURLOPT_WRITEFUNCTION, write_callback_func);
/* passing the pointer to the response as the callback parameter */
curl_easy_setopt(curl_handle, CURLOPT_WRITEDATA, &response);
/* the function to invoke as the data recieved */
size_t static write_callback_func(void *buffer,
size_t size,
size_t nmemb,
void *userp)
{
char **response_ptr = (char**)userp;
/* assuming the response is a string */
*response_ptr = strndup(buffer, (size_t)(size *nmemb));
}
请查看更多信息here。
答案 1 :(得分:4)
你需要一个写回调函数。我使用这种函数来读取响应,错误并能够提供我自己的标题:
size_t write_data(void *ptr, size_t size, size_t nmemb, void *stream)
{
std::string buf = std::string(static_cast<char *>(ptr), size * nmemb);
std::stringstream *response = static_cast<std::stringstream *>(stream);
response->write(buf.c_str(), (std::streamsize)buf.size());
return size * nmemb;
}
bool CurlGet(
const std::string &url,
const std::vector<std::string> &headers,
std::stringstream &response,
std::string &error)
{
curl_global_init(CURL_GLOBAL_ALL);
curl_slist *headerlist = NULL;
std::vector<std::string>::const_iterator it;
for (it = headers.begin(); it < headers.end(); it++) {
headerlist = curl_slist_append(headerlist, it->c_str());
}
CURL *curl = curl_easy_init();
char ebuf[CURL_ERROR_SIZE];
curl_easy_setopt(curl, CURLOPT_URL, url.c_str());
curl_easy_setopt(curl, CURLOPT_NOPROGRESS, 1);
curl_easy_setopt(curl, CURLOPT_ERRORBUFFER, ebuf);
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_data);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, &response);
curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headerlist);
CURLcode res = curl_easy_perform(curl);
curl_easy_cleanup(curl);
curl_slist_free_all(headerlist);
if (res != CURLE_OK)
error = ebuf;
else
error.clear();
return res == CURLE_OK;
}
答案 2 :(得分:2)
这可以使用
完成curl_easy_setopt(easyhandle, CURLOPT_WRITEFUNCTION, write_data);
设置回调函数write_data
,它是带签名的函数
size_t write_data(void *buffer, size_t size, size_t nmemb, void *userp);
如果您希望userp
成为您在程序中使用的内部结构,请致电
curl_easy_setopt(easyhandle, CURLOPT_WRITEDATA, &internal_struct);
将指向internal_struct
的指针传递给write_data
的每次调用。
答案 3 :(得分:1)
嗨我从回调函数解决返回代码23的问题,从回调函数返回大小。
见下面的代码:
/* setting a callback function to return the data */
curl_easy_setopt(curl_handle, CURLOPT_WRITEFUNCTION, write_callback_func);
/* passing the pointer to the response as the callback parameter */
curl_easy_setopt(curl_handle, CURLOPT_WRITEDATA, &response);
/* the function to invoke as the data recieved */
size_t static write_callback_func(void *buffer,
size_t size,
size_t nmemb,
void *userp)
{
char **response_ptr = (char**)userp;
/* assuming the response is a string */
*response_ptr = strndup(buffer, (size_t)(size *nmemb));
return ((size_t)(size *nmemb));
//if you not send return value of size it will show you ERROR CODE 23return curl_easy_perform();
}
答案 4 :(得分:0)
其他一些例子都不适用于我 这就是我最终做的事情:
size_t static curl_write(void *buffer, size_t size, size_t nmemb, void *userp)
{
userp += strlen(userp); // Skipping to first unpopulated char
memcpy(userp, buffer, nmemb); // Populating it.
return nmemb;
}
int GetCurl()
{
CURL *curl;
CURLcode res;
char *s = (char *) malloc(512);
curl = curl_easy_init();
if (curl)
{
curl_easy_setopt(curl, CURLOPT_URL, "http://www.google.com");
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, curl_write);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, s);
res = curl_easy_perform(curl);
curl_easy_cleanup(curl);
}
printf("GREAT SUCCESS!! Your string is %s\n", s);
}