Question

我的套接字程序挂起在clientsocket，address）= serversocket.accept（）并且没有吐出错误或其他任何内容。

我按照https://docs.python.org/3/howto/sockets.html

上的说明进行操作

我一直试图弄清楚它一个小时，但无济于事。我使用的是python3顺便说一句。我究竟做错了什么？编辑：我的意图全部搞砸了，因为我粘贴错了，但除此之外，我的代码就像我的文件一样。

    #import socket module
    import socket
    #creates an inet streaming socket.
    serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    print('socket created')
    #binds socket to a public host, and a well known port
    serversocket.bind(('127.0.0.1', 1024))
    #print(socket.gethostname())# on desktop prints 'myname-PC')
    #become a server socket
    serversocket.listen(5) # listens for up to 5 requests

    while True:
        #accept connections from outside
        #print('In while true loop') This works, but we never get to the next print    statement. Why the hell is it catching at line 20?
        (clientsocket, address) = serversocket.accept()
        #clientsocket = serversocket.accept()

print('Ready to serve')
#now we do something with client socket...
try:
    message = clientsocket.recv(1024)
    filename = message.split()[1]
    f = open(filename[1:])
    outputdata = f.read()
    #send an http header line
    clientsocket.send('HTTP/1.1 200 OK\nContent-Type: text/html\n\n')

    for i in range(0, len(outputdata)):
        clientsocket.send(outputdata[i])
    clientsocket.close()

except IOERROR:
    clientsocket.send('HTTP/1.1 404 File not found!')
    clientsocket.close()

Answer 1

如果你还没有编写客户端脚本/程序来连接套接字并发送数据，那么由于没有什么可以接受的，它也会挂在serversocket.accept（）上。但假设你有......

while True:
    #accept connections from outside
    #print('In while true loop') This works, but we never get to the next print    statement. Why the hell is it catching at line 20?
    (clientsocket, address) = serversocket.accept()
    #clientsocket = serversocket.accept()

它挂起，因为循环永不退出，因为True始终为True。在提供的示例中，一旦接受连接，他们就假装服务器是线程化的，并且想法是创建一个单独的线程来开始读取和处理接收到的数据，从而允许套接字继续监听更多连接。

while True:
    # accept connections from outside
    (clientsocket, address) = serversocket.accept()
    # now do something with the clientsocket
    # in this case, we'll pretend this is a threaded server
    ct = client_thread(clientsocket)
    ct.run()

Python Socket Scripting。我究竟做错了什么？

1 个答案: