Question

我有以下数据记录：

@INPROCEEDINGS{conf/icsm/Ceccato07,
  author = {Mariano Ceccato},
  title = {Migrating Object Oriented code to Aspect Oriented Programming},
  booktitle = {ICSM},
  year = {2007},
  pages = {497--498},
  publisher = {IEEE},
  bibdate = {2008-11-18},
  bibsource = {DBLP, http://dblp.uni-trier.de/db/conf/icsm/icsm2007.html#Ceccato07},
  crossref = {conf/icsm/2007},
  owner = {Administrator},
  timestamp = {2009.04.30},
  url = {http://dx.doi.org/10.1109/ICSM.2007.4362668}
}

有没有办法可以获得以下匹配，以便每一行都是一个单独的匹配

  conf/icsm/Ceccato07
  author = Mariano Ceccato
  title = Migrating Object Oriented code to Aspect Oriented Programming
  booktitle = ICSM
  year = 2007
  pages = 497--498
  publisher = IEEE
  bibdate = 2008-11-18
  bibsource = DBLP, http://dblp.uni-trier.de/db/conf/icsm/icsm2007.html#Ceccato07
  crossref = conf/icsm/2007
  owner = Administrator
  timestamp = 2009.04.30
  url = http://dx.doi.org/10.1109/ICSM.2007.4362668

这是我的模式，错过了第一行匹配，并没有删掉括号和逗号

string pattern = ".*[{].*}";

Answer 1

这个正则表达式，在单行模式下，将抓住两个外部括号内的所有内容：

(?<=\{).*(?=\})

然后你可以用C＃去除内部括号：

var regex = new Regex(@"(?<=\{).*(?=\})", RegexOptions.Singleline);
var match = regex.Match(input);

return match.Value.Replace("{", string.Empty).Replace("}", string.Empty);

嵌套花括号内的数据的正则表达式？

1 个答案: