Question

我遇到了显示前六条记录的情况。 FirstCol中的前3个记录和SecondCol中的后3个记录。我的查询是这样的：

select top 6 [EmpName] 
from [Emp ]
order by [Salary] Desc

结果：

[EmpName]
----------------------
Sam           
Pam           
Oliver        
Jam
Kim
Nixon

但我希望结果看起来像这样：

FirstCol      SecondCol
Sam           Jam
Pam           Kim
Oliver        Nixon

Answer 1

; WITH TOP_3 AS 
 (
  select TOP  3 [EmpName] 
        ,ROW_NUMBER() OVER (ORDER BY [Salary] Desc) rn 
  from [Emp ]
  order by [Salary] Desc
  ),
  Other3 AS
 (
    SELECT [EmpName] 
          ,ROW_NUMBER() OVER (ORDER BY [Salary] Desc) rn 
    FROM Employees 
    ORDER BY [Salary] DESC OFFSET 3 ROWS FETCH NEXT 3 ROWS ONLY
 )
SELECT T3.[EmpName] , O3.[EmpName]
FROM TOP_3 T3 INNER JOIN Other3 O3
ON T3.RN = O3.RN 
ORDER BY T3.RN ASC

Answer 2

你可以使用几个窗口函数来做到这一点，这有点难看，但它会得到你想要的结果：

;with data as
(
  -- get your Top 6
  select top 6 empname, salary
  from emp
  order by salary desc
), 
buckets as
(
  -- use NTILE to split the six rows into 2 buckets
  select empname, 
    nt = ntile(2) over(order by salary desc),
    salary
  from data
) 
select 
  FirstCol = max(case when nt = 1 then empname end),
  SecondCol = max(case when nt = 2 then empname end) 
from
(
  -- create a row number for each item in the buckets to return multiple rows
  select empname,
    nt,
    rn = row_number() over(partition by nt order by salary desc)
  from buckets
) d
group by rn;

见SQL Fiddle with Demo。这使用函数NTILE，这将获取六行的数据集并将其拆分为两个桶 - 桶1中的3行和桶2中的3行。(2)内的NTILE是用于确定桶的数量。

接下来，我使用row_number()为每个存储桶中的每一行创建一个唯一值，这允许您为每列返回多行。

如何获得第一个前6名记录无关紧要的列T-sql？

2 个答案: