如何创建如图像下方的梯形形状?
我不想使用图片或9.png。
答案 0 :(得分:15)
试试这个:
<?xml version="1.0" encoding="utf-8"?>
<vector xmlns:android="http://schemas.android.com/apk/res/android"
android:width="292dp"
android:height="172dp"
android:viewportWidth="292"
android:viewportHeight="172">
<path
android:strokeWidth="1.5"
android:strokeMiterLimit="10"
android:pathData="M 27.046 96.615 L 16.416 150.396 L 271.534 150.396 L 186.495 22.836 L 37.676 22.836 L 27.046 86.615 Z" />
<path
android:fillColor="#00ff00"
android:strokeWidth="1.5"
android:strokeMiterLimit="10"
android:pathData="M 16.046 20.615 L 13.416 150.396 L 271.534 150.396 L 186.495 22.836 L 37.676 22.836 L 16.046 23.615 Z " />
</vector>
答案 1 :(得分:4)
此类是View
,用于定义和绘制梯形ShapeDrawable
。因此,作为Drawable
的梯形也可用于背景中。
package com.stackoverflow.questions.q25768037;
import android.content.Context;
import android.graphics.Canvas;
import android.graphics.Color;
import android.graphics.Paint;
import android.graphics.Path;
import android.graphics.drawable.ShapeDrawable;
import android.graphics.drawable.shapes.PathShape;
import android.util.AttributeSet;
import android.view.View;
public class TrapezoidView extends View {
private ShapeDrawable mTrapezoid;
public TrapezoidView(Context context, AttributeSet attrs) {
super(context, attrs);
Path path = new Path();
path.moveTo(0.0f, 0.0f);
path.lineTo(100.0f, 0.0f);
path.lineTo(200.0f, 100.0f);
path.lineTo(0.0f, 100.0f);
path.lineTo(0.0f, 0.0f);
mTrapezoid = new ShapeDrawable(new PathShape(path, 200.0f, 100.0f));
mTrapezoid.getPaint().setStyle(Paint.Style.FILL_AND_STROKE);
mTrapezoid.getPaint().setStrokeWidth(1.0f);
mTrapezoid.getPaint().setColor(Color.GREEN);
}
@Override
protected void onSizeChanged(int w, int h, int oldw, int oldh) {
mTrapezoid.setBounds(0, 0, w, h);
}
@Override
protected void onDraw(Canvas canvas) {
mTrapezoid.draw(canvas);
}
}
答案 2 :(得分:2)
您可以尝试在代码或xml中创建LayerDrawable
。制作矩形和三角形
查看开发者网站以获取更多信息:http://developer.android.com/reference/android/graphics/drawable/LayerDrawable.html