Question

我尝试从PHP运行java但是即使我使用java可执行文件的绝对路径（C：\ Windows \ System32 \ java.exe）也不能。

我发现问题是由于某种原因，PHP无法访问此文件。我试试：

<?php var_dump(file_exists('C:\Windows\System32\java.exe')); // returns false.

文件实际存在，我（我运行php脚本的用户）有权读取和执行它。这很奇怪，因为我可以执行notepad.exe和

<?php var_dump(file_exists('C:\Windows\System32\notepad.exe')); // returns true.

有什么想法吗？

php -v 
PHP 5.3.27 (cli) (built: Jul 10 2013 20:36:59)
Copyright (c) 1997-2013 The PHP Group
Zend Engine v2.3.0, Copyright (c) 1998-2013 Zend Technologies
with Xdebug v2.2.2, Copyright (c) 2002-2013, by Derick Rethans

java -version
java version "1.7.0_40"
Java(TM) SE Runtime Environment (build 1.7.0_40-b43)
Java HotSpot(TM) 64-Bit Server VM (build 24.0-b56, mixed mode)

OS Windows 7 64位

PHPINFO：

phpinfo（）函数 PHP版本=＆gt; 27年3月5日

System => Windows NT IT8 6.1 build 7601 (Windows 7 Business Edition Service Pack 1) i586
Build Date => Jul 10 2013 20:35:35
Compiler => MSVC9 (Visual C++ 2008)
Architecture => x86
Configure Command => cscript /nologo configure.js  "--enable-snapshot-build" "--enable-debug-pack" "--disable-zts" "--disable-isapi" "--disable-nsapi" "--without-mssql" "--without-pdo-mssql" "--without-pi3web" "--with-pdo-oci=C:\php-sdk\oracle\instantclient10\sdk,shared" "--with-oci8=C:\php-sdk\oracle\instantclient10\sdk,shared" "--with-oci8-11g=C:\php-sdk\oracle\instantclient11\sdk,shared" "--with-enchant=shared" "--enable-object-out-dir=../obj/" "--enable-com-dotnet=shared" "--with-mcrypt=static" "--disable-static-analyze"
Server API => Command Line Interface
Virtual Directory Support => disabled
Configuration File (php.ini) Path => C:\Windows
Loaded Configuration File => C:\Program Files (x86)\PHP\php.ini
Scan this dir for additional .ini files => (none)
Additional .ini files parsed => (none)
PHP API => 20090626
PHP Extension => 20090626
Zend Extension => 220090626
Zend Extension Build => API220090626,NTS,VC9
PHP Extension Build => API20090626,NTS,VC9
Debug Build => no
Thread Safety => disabled
Zend Memory Manager => enabled
Zend Multibyte Support => disabled
IPv6 Support => enabled
Registered PHP Streams => php, file, glob, data, http, ftp, zip, compress.zlib, compress.bzip2, https, ftps, phar, ssh2.shell, ssh2.exec, ssh2.tunnel, ssh2.scp, ssh2.sftp
Registered Stream Socket Transports => tcp, udp, ssl, sslv3, sslv2, tls
Registered Stream Filters => convert.iconv.*, mcrypt.*, mdecrypt.*, string.rot13, string.toupper, string.tolower, string.strip_tags, convert.*, consumed, dechunk, zlib.*, bzip2.*

Answer 1

如果你想使用php运行java，你必须使用php-jaja-bridge.see这里：http://php-java-bridge.sourceforge.net/pjb/

获取更多帮助，请看： http://darrylclarke.com/2008/03/04/installing-php-java-bridge-on-ubuntu/

Answer 2

建议：
从PHP.net到file_exists：

This function returns FALSE for files inaccessible due to safe mode restrictions. However these files still can be included if they are located in safe_mode_include_dir.

此外：
file_exists的结果将被缓存。
也许您必须致电clearstatcache()

修改：
您可以尝试以下操作：

<?php var_dump(file_exists("C:\\Windows\\System32\\java.exe"));

Answer 3

遇到同样的问题并通过重新定位java.exe解决了这个问题从Windows / System32文件夹到例如C：/ Java的（假设可执行文件C：/Java/java.exe现在实际存在）＆＃39; file_exists（＆＃34; C：/Java/java.exe"）＆＃39; （和＆＃39; is_executable（＆＃34; C：/Java/java.exe"）＆＃39;）现在应该回归真实。

从PHP脚本运行java

3 个答案: