Question

**这个问题是指从MySQL传递文件，而不是从URL传递文件。因此，请仔细检查您是否愿意将其标记为重复**

我试图通过php将图像（存储为BLOB）从MySQL传递给android。在PHP中我正在做：

function getimage($id)
{
     $sql = "SELECT mime,data, evimagename FROM evidence
    WHERE transactionID = :transactionID";

    $stmt = $this->conn->prepare($sql);
    $stmt->execute(array(":transactionID" => $id));
    $stmt->bindColumn(1, $mime);
    $stmt->bindColumn(2, $data, PDO::PARAM_LOB);
    $stmt->bindColumn(3, $imgname);

     $stmt->fetch(PDO::FETCH_BOUND);

     return array("mime" => $mime,
         "data" => $data,"imgname"=>$imgname);
}

并将此功能称为：

   $result = $blobObj->selectBlob($trid);
   $file= $result['data'];
   header("Content-Type:application/json");
   header('Content-Description: File Transfer');
   header('Content-Transfer-Encoding: binary');
   header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
   header('Pragma: public');
   header('Expires: 0');
   $filename = $a['imgname'];
   header('Content-Disposition: attachment;filename='.$filename.".jpeg");
   $encoded = base64_encode($file);
   echo json_encode(array('image'=>$encoded));

在android中，我试图将这个json_encoded文件作为：

   HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(
                "http://10.1.1.5/connect/getevimage.php");

        try {

            List<BasicNameValuePair> nameValuePairs = new ArrayList<BasicNameValuePair>();
            String trid = arg0[0];
            nameValuePairs.add(new BasicNameValuePair("TRID", trid));

            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            HttpResponse response = httpclient.execute(httppost);
            InputStream content = response.getEntity().getContent();
            String responsestring = content.toString();

            Log.d("chddeck",responsestring);
            long filesize = response.getEntity().getContentLength();
            Log.d("filesize",String.valueOf(filesize));

在我的日志中，我可以看到响应字符串为

org.apache.http.conn.EofSensorInputStream@41a2fc58

，文件大小为-1。我搜索了很多，但无法找到任何线索。你能指出我哪里出错吗？

Answer 1

替代方法可以是

方法1：

使用图像路径，因为某些博客数据可能很大程度上需要输入字符串变量，因此可能会因为你在字符串变量中收到完整的博客而被破坏...

方法2：

使用lib在服务器上直接上传图像

小代码片段：

mFtpClient.connect(InetAddress.getByName(server));
mFtpClient.login(user, password);
mFtpClient.changeWorkingDirectory(serverRoad);
mFtpClient.setFileType(FTP.BINARY_FILE_TYPE);
BufferedInputStream buffIn=null;
buffIn=new BufferedInputStream(new FileInputStream(file));
mFtpClient.enterLocalPassiveMode();
mFtpClient.storeFile("test.txt", buffIn);
buffIn.close();
mFtpClient.logout();
mFtpClient.disconnect();

Link

使用JSON将图像文件从MySql发送到android.-文件未传递

1 个答案: