我是PHP的新手。我试图将两个从表单上传的文件发送到电子邮件发送给自己。这可能很容易,但是在过去的三个小时里还没有得到它。
我已设法获取您看到的文件信息。你怎么附上这些?这就是我遇到麻烦的地方。
这是从表单接收两个文件(和其他数据)的代码..如果有帮助,该网站是SermonPublish.com。
感谢您的帮助。
标准获取变量。
<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {
$cover = "cover: " . test_input($_POST["cover"]) . "\n";
$authorname = "Author Name: " . test_input($_POST["authorName"]) . "\n";
$booktitle = "Title: " . test_input($_POST["bookTitle"]) . "\n";
$subtitle = "Subtitle: " . test_input($_POST["subtitle"]) . "\n";
$description = "Description: " . test_input($_POST["description"]) . "\n";
$aboutauthor = "About Author: " . test_input($_POST["aboutAuthor"]) . "\n";
$clientnumber = "Client Number: " . test_input($_POST["clientNumber"]) . "\n";
$payment = "Payment: " . test_input($_POST["payment"]) . "\n";
$address = "Address: " . test_input($_POST["address"]) . "\n";
$agreement = "Agree: " . test_input($_POST["agreement"]) . "\n";
$email = test_input($_POST["email"]);
获取有关文件上传的详细信息。
//Get the uploaded file information
$author_photo_name =
basename($_FILES['authorPhoto']['name']);
$author_photo_type =
substr($author_photo_name,
strrpos($author_photo_name, '.') + 1);
$author_photo_size =
$_FILES["authorPhoto"]["size"]/1024;//size in KBs
//Get the uploaded file information
$sermon_name =
basename($_FILES['sermon']['name']);
$sermon_type =
substr($sermon_name,
strrpos($sermon_name, '.') + 1);
$sermon_size =
$_FILES["sermon"]["size"]/1024;//size in KBs
}
好的,现在你怎么附上?
标准邮寄代码
$subject = "Sermon Submission";
$message = $cover . $authorname . $booktitle . $subtitle . $description . $aboutauthor . $clientnumber . $payment . $address . $agreement . $email;
$message = wordwrap($message, 70);
// send mail
mail("wibberding@gmail.com",$subject,$message,"From: $email\n");
echo "Thank you for your submission. We will contact you as soon as it is processed.";
?>
答案 0 :(得分:0)
我按照建议使用了PHPMailer。效果很好。