Question

对于php来说，我是一个完整的新手，我有以下的php，它会向我发回消息＆＃39;并向用户发送自动回复，并将其重定向到“谢谢你”。页。我遇到的问题是它不会返回他们在表单上填写的用户名，任何想法？

<?php

$youremail = "ally.baird81@gmail.com"; //this is where the email will be sent to

@extract($_POST);$name = filter_var($name, FILTER_SANITIZE_STRING);
$message  = filter_var($message, FILTER_SANITIZE_STRING);

if (filter_var($email, FILTER_VALIDATE_EMAIL)) {
    if (mail($youremail, 'Message from website.', $message, "From: Krew Kut Hair<$email>")) {

        $autoreply = "Thank you for enquiring at Krew Kut Hair, we will be in contact shortly";
        $subject   = "Thank you for your enquiry!";
        mail($email, $subject, $autoreply, "From: Krew Kut Hair<$email>");

    }
} else {
    echo "Please enter a valid email address";
}

header("Location: thanks.html");

Answer 1

如果您输入名为＆＃34; name＆＃34;像：

<input type="text" name="name" value="" />

检查它是否包含数据，例如：

echo 'The value of name is ['.$name.']';

如果它包含数据，您可以在邮件中使用$name变量。如果不是HTML格式可能有问题。

<?php

$youremail = "ally.baird81@gmail.com"; //this is where the email will be sent to

@extract($_POST);$name = filter_var($name, FILTER_SANITIZE_STRING);
$message    = filter_var($message, FILTER_SANITIZE_STRING);
$content    = "<strong>Name:<strong><br />".$name."<br />";
$content   .= "<strong>Message:<strong><br />".$message."<br />";

if (filter_var($email, FILTER_VALIDATE_EMAIL)) {
    if (mail($youremail, 'Message from website.<br />', $content, "From: Krew Kut Hair<$email>")) {

        $autoreply = "Hi ".$name.". Thank you for enquiring at Krew Kut Hair, we will be in contact shortly";
        $subject   = "Thank you for your enquiry!";
        mail($email, $subject, $autoreply, "From: Krew Kut Hair<$email>");

    }
} else {
    echo "Please enter a valid email address";
}

header("Location: thanks.html");

同时阅读有关您问题的评论。我强烈建议您使用其他方法，而不是使用extract()。

Answer 2

假设名称位于其中一个表单字段中，您应该能够检索它。正如Barmar所说 - 你所要做的就是在身体或信息的某个地方使用它。如果你不在某个地方回应它，怎么能告诉你名字丢失了。试试这个：

$autoreply = "Thank you ".$name."  for ...

如果名称仍然“缺失” - 您可以尝试查看所有的帖子变量：

echo "<PRE>Post Vars\n"; print_r($_POST);

PHP表单返回所有信息

2 个答案: