数字到唯一字符组合

Question

我想为PHP中的1-infinity中的每个数字创建一个字符组合。

允许的字符是a-z

• 0 - ＆gt;一个
• 1 - ＆gt; B'/ LI>
• 2 - ＆gt; ç
• ...
• 25 - ＆gt; ž
• 26 - ＆gt; AA
• 27 - ＆gt; AB

我希望你明白我的意思。谢谢！

Answer 1

添加内联的所有评论。

//Your number
$num = 700;

//Stores the result
$result = "";

$count = 0;
while ($num>=1)
{
    /*If we don't do the following line,
    26 will be "ba" but not "aa"
    As a number 2 can be written as 02 in decimal, but in your example we can't do that, as you won't allow writing 02 as "ac", but simply "c".*/
    if ($num < 26) $offset=9; else $offset=10;

    //The following part is just a simple base conversion
    $remainder = $num%26;
    $digit =  base_convert($remainder+$offset,10,36);
    $result .= $digit;
    $num = floor($num/26);

    $count++;
}

//Display in reverse order
$result = strrev($result);
echo $result;