Swift:不符合协议NSCoding

时间:2014-09-09 16:54:25

标签: ios iphone swift nscoding

我正在尝试在我用swift编写的类上使用NSCoding协议,但是当我实现所需的方法时,似乎无法弄清楚为什么编译器会抱怨它“不符合协议NSCoding”:

class ServerInfo: NSObject, NSCoding {

    var username = ""
    var password = ""
    var domain = ""
    var location = ""
    var serverFQDN = ""
    var serverID = ""

    override init() {

    }

    init(coder aDecoder: NSCoder!) {
        self.username = aDecoder.decodeObjectForKey("username") as NSString
        self.password = aDecoder.decodeObjectForKey("password") as NSString
        self.domain = aDecoder.decodeObjectForKey("domain") as NSString
        self.location = aDecoder.decodeObjectForKey("location") as NSString
        self.serverFQDN = aDecoder.decodeObjectForKey("serverFQDN") as NSString
        self.serverID = aDecoder.decodeObjectForKey("serverID") as NSString
    }


    func encodeWithCoder(_aCoder: NSCoder!) {
        _aCoder.encodeObject(self.username, forKey: "username")
        _aCoder.encodeObject(self.password, forKey: "password")
        _aCoder.encodeObject(self.domain, forKey: "domain")
        _aCoder.encodeObject(self.location, forKey: "location")
        _aCoder.encodeObject(self.serverFQDN, forKey: "serverFQDN")
        _aCoder.encodeObject(self.serverID, forKey: "serverID")
    }

}

这是一个错误还是我错过了什么?

3 个答案:

答案 0 :(得分:19)

正如您在报告导航器中的详细编译器消息中所看到的, 您的方法未正确声明:

error: type 'ServerInfo' does not conform to protocol 'NSCoding'
class ServerInfo: NSObject, NSCoding {
^
Foundation.NSCoding:2:32: note: protocol requires function 'encodeWithCoder' with type '(NSCoder) -> Void'
  @objc(encodeWithCoder:) func encodeWithCoder(aCoder: NSCoder)
                               ^
note: candidate has non-matching type '(NSCoder!) -> ()'
    func encodeWithCoder(_aCoder: NSCoder!) {
         ^
Foundation.NSCoding:3:25: note: protocol requires initializer 'init(coder:)' with type '(coder: NSCoder)'
  @objc(initWithCoder:) init(coder aDecoder: NSCoder)
                        ^
note: candidate has non-matching type '(coder: NSCoder!)'
    init(coder aDecoder: NSCoder!) {

(这可能在测试版发布之间发生了变化。) 此外,initWithCoder方法必须标记为required

required init(coder aDecoder: NSCoder) {   }

func encodeWithCoder(_aCoder: NSCoder) {   }

Swift 3 中,所需的方法是

required init(coder aDecoder: NSCoder) {   }

func encode(with aCoder: NSCoder) {   }

答案 1 :(得分:4)

参数不会被隐式展开(删除!),初始化程序需要required修饰符:

required init(coder aDecoder: NSCoder) {
...
func encodeWithCoder(_aCoder: NSCoder) {

适用于Swift 3

已经承诺了一个小但重要的变化。 init方法相同,但encodeWithCoder方法已被修改。

   required init(coder aDecoder: NSCoder) {
    ...
   }

   func encode(with _aCoder: NSCoder) { 
   ...
   }

答案 2 :(得分:0)

对于Swift 3(在Xcode 8.2 beta(8C23)上)

它似乎又改变了。这是我可以开始工作的唯一变体......

func encodeWithCoder(_ _aCoder: NSCoder) {
    ...
}