Question

伙计我试图从mysql数据库中获取一些结果，并且我在将其提取到scala.html文件时出错。这是我的代码：

/*Customers.scala. Its controller*/
package controllers

import play.api._
import play.api.mvc._
import models.Customers

object Customers extends Controller{

    def customer = Action{

        val nb_customers = Customers.allCustomers

        Ok(views.html.customer(nb_customers)) //I am having error here.

    }
    // End of customer Action.

}
// End of Customer controller.



/*Now Customers.scala model*/

package models
import anorm._
import play.api.db._
import play.api.Play.current

case class Customers(CustomersID: Int, Name: String)

object Customers {

    def allCustomers = {

        DB.withConnection {implicit connection =>

            SQL("Select * from Customers")().map{row =>

                Customers(

                    CustomersID = row[Int]("CustomersID"),
                    Name = row[String]("Name")

                )
                // End of Customers object.
            }.toList
            // SQL ends.

        }
        // With connection.

    }
    // End of allCustomers.

}
// End of of Customers.

请注意，我在conf / application.conf文件中使用JDBC驱动程序进行mysql连接

请帮帮我。非常感谢。

Answer 1

您的Customers控制器和模型之间存在命名空间冲突，因为两者都在范围内。你可以做两件事来解决这个问题。

将您的模型重命名为其他内容，例如Customer。
将Customers.allCustomers更改为models.Customers.allCustomers，以区别于controllers.Customers。

用mysql结果无法解析符号scala play2

1 个答案: