Question

我可以使用一些帮助来弄清楚为什么我的游戏不允许我拿起一把剑。出现的错误消息是

追踪（最近一次通话）：文件“”，第36行，in 文件“”，第1行，in NameError：名称'y'未定义

这是基本游戏，我对此非常陌生，所以简单的术语会很好。

print 'You enter a Dungeon with three doors. Do you want to enter door #1 door #2 or door #3?'
door = raw_input('> ')

if door == "1":
    print 'Theres a dragon eating a human, the dragon is massive and looks terrifying'
    print 'what do you want to do?'
    print '#1 try to save the human'
    print '#2 scream and run around'
    dragon = raw_input('> ')

    if dragon == "1":
        print 'You approach the dragon sneakily. After what feel like a thousand years you are finally close to the dragon. You try to step closer. The dragon shifts and crushes you. Well done!'

    elif dragon == "2":
        print 'You scream and run around like a chicken with no head. The dragon is not impressed with you. It snorts and engulfs you in flames. You die a painful and worthless death. Well done!'

elif door == "2":
    print 'You stare into a deep dark cave.'
    print 'Oh dear, it seems you have been driven you quite insane.'
    print '#1. drool'
    print '#2. scream, drool, and walk forward'
    print '#3. Understand computer programming completely and get an A plus'
    insanity = raw_input('> ')

    if insanity == "1":
        print 'Your body survives but your mind does not, you drool for eternity!'

    if insanity == "2":
        print 'You slip on a mysterious liquid, then fall into a deep sleep, you awake years later at the kiss of a prince. Yay!'

    if insanity == "3":
        print 'Congradulations! You passed Programming! Time to graduate and face the real world.. So I guess you actully lost. Sorry.'

elif door == "3":
    print ("You emerge into a brighter area and see a small sword lying on the ground")
    ch1 = str(input("Do you take it? [y/n]:"))
    if ch1 == "y":
        print 'You have taken the sword!'
        stick = 1

else:
    print 'You have chosen not to take the sword'
    sword = 0

Answer 1

ch1 = str(input("Do you take it? [y/n]:"))

如果您使用input且用户键入＆＃34; y＆＃34;，解释程序将搜索变量y并返回其值。您没有y变量，因此崩溃了。你可能想在这里使用raw_input，而不是input。

ch1 = str(raw_input("Do you take it? [y/n]:"))

顺便说一句，raw_input无论如何都会返回一个字符串，因此您并不需要str来电。

ch1 = raw_input("Do you take it? [y/n]:")

Answer 2

答案已更正：

使用 raw_input 代替input

In [32]: ch1 = raw_input("Do you take it? [y/n]:")
Do you take it? [y/n]:y

In [33]: ch1
Out[33]: 'y'

基于Python文本的冒险游戏，需要帮助

2 个答案: