Question

我有两个时间戳让我们说

 $end_date =  2014-09-09 15:03:10 and now date 
 date_default_timezone_set('Asia/Calcutta'); 
 $now = date('Y-m-d H:i:s');

我想计算剩余的天数。假设特定日期现在越过现在的日期，它应该显示剩余天数-ve值。

我正在使用以下代码

$remaining_days =strtotime($end_date) - strtotime($now) ;
$Result_days = floor($remaining_days /86400);
echo $remaining_days.'   '.$Result_days.'<br/>'

问题是，如果结束日期=今天的日期，则显示-1。我想根据时间计算并显示剩余的天数和小时数。请帮我找出解决方案。

Answer 1

试试这个：

<?php
$end_date =  "2014-10-09 15:03:10";
date_default_timezone_set('Asia/Calcutta'); 
$now = date('Y-m-d H:i:s');

$diff = strtotime($now) - strtotime($end_date);
$fullDays    = floor($diff/(60*60*24));   
$fullHours   = floor(($diff-($fullDays*60*60*24))/(60*60));   
$fullMinutes = floor(($diff-($fullDays*60*60*24)-($fullHours*60*60))/60);      
echo "Difference is $fullDays days, $fullHours hours and $fullMinutes minutes.";

的输出：

差异是-30天，0小时39分钟。

的演示：

http://3v4l.org/3auqe

编辑（使用日期对象）：

<?php // Example 1 $end_date = "2014-09-11 20:35:10"; date_default_timezone_set('Asia/Calcutta'); $now = date('Y-m-d H:i:s'); $date1=date_create($now); $date2=date_create($end_date); $diff=date_diff($date1,$date2,FALSE); echo $diff->format("%R%d days, %h hours, %m minutes, %s seconds").PHP_EOL; //Output: +2 days, 3 hours, 0 minutes, 44 seconds // Example 2 $end_date = "2014-09-08 20:35:10"; date_default_timezone_set('Asia/Calcutta'); $now = date('Y-m-d H:i:s'); $date1=date_create($now); $date2=date_create($end_date); $diff=date_diff($date1,$date2,FALSE); echo $diff->format("%R%d days, %h hours, %m minutes, %s seconds").PHP_EOL; //Output: -0 days, 20 hours, 0 minutes, 16 seconds

的演示：

http://3v4l.org/dPSgX#vhhvm-320

Answer 2

您可以使用date_diff php方法。您可以在此处查看示例http://php.net/manual/en/function.date-diff.php

Answer 3

您可以尝试这样：

<?php   
    $dateDiff    = $date1 - $date2;   
    $fullDays    = floor($dateDiff/(60*60*24));   
    $fullHours   = floor(($dateDiff-($fullDays*60*60*24))/(60*60));   
    $fullMinutes = floor(($dateDiff-($fullDays*60*60*24)-($fullHours*60*60))/60);      
    echo "Differernce is $fullDays days, $fullHours hours and $fullMinutes minutes.";   
?>

有关更多选项，请参阅Source

$date1 = new DateTime("2014-09-09");
$date2 = new DateTime("2014-09-12");
$interval = $date1->diff($date2);
echo "difference " . $interval->y . " years, " . $interval->m." months, ".$interval->d." days ";

duplicate

php中两个timestamp变量的区别

3 个答案: