Question

我的代码：

 if (numavg <=3 ){
             Console.WriteLine("Congratz, we can start! but some note before :");
             Console.WriteLine("When you put the last number, type 'c' in the next line for calculate the avg");
             Console.WriteLine("So lets start! type the first number.");
             avg1 = int.Parse(Console.ReadLine());
             Console.WriteLine("Ok, so you choose " + avg1 + ",who is the next number?");
             avg2 = int.Parse(Console.ReadLine());
             Console.WriteLine("Wonderful! put the next number");
             avg3 = int.Parse(Console.ReadLine());
             if (avg3 = "c"){
                 Console.WriteLine("Ok, Lets calculate!");
                 average = (avg1 + avg2)/numavg;
                 Console.WriteLine("The average is " + average + ".");


             }
             else {
                 Console.WriteLine("Perfect! please type the next number,or 'c' for avg to the last 3 numbers.");
                 avg4 = int.Parse(Console.ReadLine());


                 if (avg4 = "c" ){
                     Console.WriteLine("Ok, Lets calculate!");
                     average1 = (avg1 + avg2 + avg3)/numavg;
                     Console.WriteLine("The average is " + average1 + ".");



             }

         }

问题在于类型“c”（用于计算平均值）。我不明白如何将avg3和avg4保持为字符串和整数。

帮助？

更纯粹的问题 - 如果我希望程序结束并自动重启，我需要键入哪些代码？（如果无法重启，我怎样才能完成自动程序关闭的第一件事？）

谢谢你们！

注意：错误是“无法将类型'字符串'隐式转换为'int'”。

Answer 1

您的意思是if(avg3 == "c")而不是if (avg3 = "c")

(avg3 = "c")您要将"c"分配给avg3 int，其类型为" Cannot implicitly convert type 'string' to 'int'".

String avg3Str = Console.ReadLine();
if (avg3Str.equals("c")){
 Console.WriteLine("Ok, Lets calculate!");
 average = (avg1 + avg2)/numavg;
 Console.WriteLine("The average is " + average + ".");
}
else {
 avg3 = int.Parse(avg3Str);
 Console.WriteLine("Perfect! please type the next number,or 'c' for avg to the last 3 numbers.");
 String avg4Str = Console.ReadLine();
 if (avg4Str.equals("c") ){
     Console.WriteLine("Ok, Lets calculate!");
     average1 = (avg1 + avg2 + avg3)/numavg;
     Console.WriteLine("The average is " + average1 + ".");
 }
 else
 {
  avg4 = int.Parse(avg4Str);
  Console.WriteLine("Ok, Lets calculate!");
     average1 = (avg1 + avg2 + avg3 + avg4)/numavg;
     Console.WriteLine("The average is " + average1 + ".");
 }

}

Int和string在一起

1 个答案: