我有书籍,有作者和编辑。我想查询所有标题为'%off%和author.name的书籍,如'%paul%' - 我无法找到关于这样做的文档,但我已根据我用Google搜索的内容尝试了各种格式。
尝试使用过滤器包括:
var includes = [
{"model": db.User, as: 'Author', through: {"where": {"name": { like: '%paul%'}}}}
];
var filter = { title: { like: '%gone%'}};
return Book.findAll({ include: includes, order: 'id desc', where: filter});
虽然对标题的限制有效,但作者姓名被忽略(没有错误)。
没有'到'的变化(结果相同 - 不影响结果集):
var includes = [
{"model": db.User, as: 'Author', "where": {"name": { like: '%paul%' } } }
];
我主动认为它可能会起作用(导致错误):
var filter = { title: { like: '%gone%'}, 'author.name' : { like : '%paul%' } };
任何有关文档的线索或指示可以帮助我做到这一点?
感谢。
型号:
var User = sequelize.define('User', {
name: {
type: DataTypes.STRING
},
...
classMethods: {
associate: function (models) {
User.hasMany(Book, { as: 'Author', foreignKey: 'author_id' });
User.hasMany(Book, { as: 'Editor', foreignKey: 'editor_id' });
},
...
}
var Book = sequelize.define('Book', {
title: {
type: DataTypes.STRING,
len: [20]
},
...
classMethods: {
associate: function (models) {
Book.belongsTo(User, { as: 'Author', foreignKey: 'author_id' });
Book.belongsTo(User, { as: 'Editor', foreignKey: 'editor_id' });
},
...
答案 0 :(得分:1)
我通过删除' as'在预订的用户关联中:
User.hasMany(Book, { foreignKey: 'author_id' });
User.hasMany(Book, { foreignKey: 'editor_id' });
然后我可以按预期过滤:
var includes = [
{model: db.User, as: 'Author'},
{model: db.User, as: 'Editor'}
];
var filter = { title: { like: '%gone%'}, 'Author.name' : { like : '%paul%' } };
return Book.findAll({ include: includes, order: 'id desc', where: filter});
它有助于打开SQL语句的日志记录,如下所述:How can I see the SQL generated by Sequelize.js?