如何解析android上的json对象有谁帮忙了？

Question

[{     “类别”：“地址”，     “AddressDetail”：[{         “标题”：“Dunya Ticaret Merkezi”，         “手机”： “747”，         “纬度”：“39.903712”，         “经度”：“32.865229”     }，{         “标题”：“Tepe Prime”，         “手机”： “737”，         “纬度”：“39.910020”，         “经度”：“32.755583”     }] }]

Answer 1

我的代码是......像这样，如何改变正确的形式？

String strJson =“{[{\”Category \“：\”Addresses \“，\”AddressDetail \“：[{\”Title \“：\”Dunya Ticaret Merkezi \“，”                 +“\”Phone \“：\”747 \“，\”Latitude \“：\”39.903712 \“，\”经度\“：\”32.865229 \“}，”                 +“{\”Title \“：\”Tepe Prime \“，\”Phone \“：\”737 \“，\”Latitude \“：\”39.910020 \“，\”经度\“：\”32.755583 \ “}]}]}”;

           String data = "";


           try {
                JSONObject jsonObj = new JSONObject(strJson);


                JSONArray jarRow = jsonObj.getJSONArray("Category");
                for(int i=0;i<jarRow.length(); i++){
                    // creating an object first
                    JSONObject ElementsObj = jarRow.getJSONObject(i);
                    // and getting the array out of the object
                    JSONArray jarElements = ElementsObj.getJSONArray("AddressDetail");
                    for(int j=0; j<jarElements.length(); j++){
                        JSONObject distanceObj = jarElements.getJSONObject(j).getJSONObject("distance");
                        String distanceStr = distanceObj.getString("Title");
                        int Phone = distanceObj.getInt("Phone");
                        Log.v("finally getting distance : ", distanceStr);
                    }
                }

            } catch (JSONException e) {
                e.printStackTrace();
            }