我遇到了在ArrayList中循环/返回正确项目的问题。当我运行我的程序,并使用我的访问器方法时,它返回终端中的项目,如“Member @ 13243”,而不是我试图返回的实际成员。我有两个班,一个是“家庭”,一个是“会员”。
我的任务是: 2)getMembers() - 返回已添加到Family的成员列表。 3)getMembers(string s) - 返回已添加到Family的成员列表。 一个。如果指定的性别无效,则应输出错误。 4)showMembers() - 使用Member的toString打印已添加到Family的成员列表 5)showMembers(字符串s) - 使用Member的toString打印已添加到一个系列的成员列表 指定的性别。
我的家庭代码:
public class Family
{
// instance variables - replace the example below with your own
public int ID;
public String FamilyName;
public String Address;
public String City;
public String State;
public String ZipCode;
public ArrayList<Member> list;
public Family(int ID, String FamilyName, String Address, String City, String State, String ZipCode)
{
this.ID = ID;
this.FamilyName = FamilyName;
this.Address = Address;
this.City = City;
this.State = State;
this.ZipCode = ZipCode;
list = new ArrayList<Member>();
}
public void addMember(Member m ) {
list.add(m);
}
private ArrayList<Member> getMembers(){
return list;
}
public void showAll(){
System.out.println(ID);
System.out.println(Member.memberName);
System.out.println(FamilyName);
System.out.println(Member.memberSex);
System.out.println(Address);
System.out.println(City);
System.out.println(State);
System.out.println(ZipCode);
}
我的班级成员代码:
public class Member
{
private String memberName;
private String memberSex;
public Member(String memberName, String memberSex){
this.memberName = memberName;
this.memberSex = memberSex;
if (memberSex == "M"){
memberSex = "M";}
else if (memberSex == "F"){
memberSex = "F";}
else System.out.println("Please enter M or F for sex");
}
public String getMemberName(){
return memberName;
}
public String getMemberSex(){
return memberSex;
}
答案 0 :(得分:0)
您应该在Member类中覆盖toString方法。
@Override
public String toString() {
return "Member: "+memberName, "Sex "+memberSex;
}