Question

我有以下代码，如下所示代码正在运行但底部对我来说效率非常低，所以我想知道是否有人有任何想法如何重写代码以便它不需要创建

baseUrl + '<?php echo $urls[0]; ?>',

每一行？

（$ urls只包含这样的文字：更多东西（所以没有http：等等））

<?php
    include("includes/connect.php");
    $sql = mysql_query("SELECT url FROM urls ORDER BY listorder ASC");

    $urls = array();

    while ($rw = mysql_fetch_array($sql)) {
        $urls[] = $rw['url'];
    }
?>

<script>
var baseUrl = '/';

var mySwipe = $('#pageBody').responsiveSwipe({
    edition: [
        baseUrl,
        baseUrl + '<?php echo $urls[0]; ?>',
        baseUrl + '<?php echo $urls[1]; ?>',
        baseUrl + '<?php echo $urls[2]; ?>',
        baseUrl + '<?php echo $urls[3]; ?>',
        baseUrl + '<?php echo $urls[4]; ?>',
        baseUrl + '<?php echo $urls[5]; ?>',
        baseUrl + '<?php echo $urls[6]; ?>',
        baseUrl + '<?php echo $urls[7]; ?>',
        baseUrl + '<?php echo $urls[8]; ?>',
        baseUrl + '<?php echo $urls[9]; ?>',
        baseUrl + '<?php echo $urls[10]; ?>'
    ],
    widthGuess: 0,
    emulator: window.location.hash.match(/emulator/)
});

$(document).ready(function(){
    $(document).on('click', '.next', function (e) {
        e.preventDefault();
        mySwipe.gotoNext();
    });
    $(document).on('click', '.prev', function (e) {
        e.preventDefault();
        mySwipe.gotoPrev();
    });
})
</script>

Answer 1

您可以在生成数组（包括baseUrl）服务器端后使用json_encode：

<?php
    ...

    $baseUrl = '/';

    $urls = array($baseUrl);

    while ($rw = mysql_fetch_array($sql)) {
        $urls[] = $baseUrl.$rw['url'];
    }
?>

<script>
var mySwipe = $('#pageBody').responsiveSwipe({
    edition: <?php echo json_encode($urls); ?>,
    widthGuess: 0,
    emulator: window.location.hash.match(/emulator/)
});

...
</script>

Answer 2

你可以在你的php中做这样的事情：

$java_urls = '';
foreach ($urls as $url)
{
$java_urls .= "'/".$url."',";
}
// remove last , from the string
if ($java_urls!='') { $java_urls = substr($java_urls, 0, -1); }

现在在你的javascript：

var mySwipe = $('#pageBody').responsiveSwipe({
    edition: [
        baseUrl,
        <?php echo $java_urls;?>
    ],
    widthGuess: 0,
    emulator: window.location.hash.match(/emulator/)
});

Answer 3

此：

var mySwipe = $('#pageBody').responsiveSwipe({
    edition: [
        baseUrl,
        baseUrl + '<?php echo $urls[0]; ?>',
        baseUrl + '<?php echo $urls[1]; ?>',
        baseUrl + '<?php echo $urls[2]; ?>',
        baseUrl + '<?php echo $urls[3]; ?>',
        baseUrl + '<?php echo $urls[4]; ?>',
        baseUrl + '<?php echo $urls[5]; ?>',
        baseUrl + '<?php echo $urls[6]; ?>',
        baseUrl + '<?php echo $urls[7]; ?>',
        baseUrl + '<?php echo $urls[8]; ?>',
        baseUrl + '<?php echo $urls[9]; ?>',
        baseUrl + '<?php echo $urls[10]; ?>'
    ],

也可能像

var mySwipe = $('#pageBody').responsiveSwipe({
   edition: [
   <?php
   foreach($urls as $url) {
      echo '/'.$url.',';
   }
   ?>
   ]
})

效率低下的php / javascript代码？

3 个答案: