我正在制作表格,我需要输入每个时期的时间,例如。
这些记录可以像我的例子一样保存在列表框中。另一种形式我有3个标签 CurrentTime,TimePassed,TimeLeft和Timer,间隔为1秒。因此,在应用程序打开时,时间流逝,时间停止,当前时间显示正确的时间。
在最后它看起来像这样
Private Sub cmdAdd_Click()
Call addp
End Sub
Function addp(Optional ByVal t As String)
Dim s As String, e As String
If t = "" Then s = Trim(InputBox("Start time (hh:mm AM/PM):")) Else: s = Trim(Split(t, "-")(0))
If s = "" Or InStr(1, s, " AM") = 0 And InStr(1, s, " PM") = 0 Then Exit Function
If chk(s) = False Then Exit Function
If t = "" Then e = Trim(InputBox(s & "-?" & vbCrLf & "End time:")) Else: e = Trim(Split(t, "-")(1))
If e = "" Or InStr(1, e, " AM") = 0 And InStr(1, e, " PM") = 0 Then Exit Function
If e = s Then Exit Function
If chk(e) = False Then Exit Function
If Format$(Split(s, "-")(0), "hh:mm AM/PM") > Format$(Split(e, "-")(0), "hh:mm AM/PM") Then Exit Function
If lstPeriods.List(0) <> "" Then
If Format$(Split(lstPeriods.List(lstPeriods.ListCount - 1), "-")(1), "hh:mm AM/PM") > Format$(Split(s, "-")(0), "hh:mm AM/PM") Then Exit Function
End If
lstPeriods.AddItem lstPeriods.ListCount + 1 & ". " & s & "-" & e
If frmMain.lblPeriod.Caption = "" Then Call snd(s & "-" & e, lstPeriods.ListCount)
End Function
进行检查
Function chk(ByVal st As String) As Boolean
st = Replace$(Replace$(st, " AM", ""), " PM", "")
If UBound(Split(st, ":")) <> 1 Then Exit Function
For i = 0 To 1
If IsNumeric(Split(st, ":")(i)) = False Then Exit Function
If Len(Split(st, ":")(i)) <> 2 Then Exit Function
If Split(st, ":")(i) < 0 Then Exit Function
Next
If Split(st, ":")(0) > 12 Then Exit Function
If Split(st, ":")(1) > 59 Then Exit Function
chk = True
End Function
我给出的解决方案是我唯一的初学者解决方案。而且我知道它很混乱而且很慢。使用trim / split / format是无法完成的,因为它需要进行大量修改。
寻找更简单的解决方案。
我需要将计算机上的当前时间与文本框/列表框中的人员时间进行比较,我该怎么做。
答案 0 :(得分:1)
要运行此代码,您需要向Form1
添加5个控件lblSystemTime = Label Control
lblTimeLeft = Label Control
lblTimePassed = Label Control
lblPeriod = Label Control
tmrSystemTime = Timer Control
Dim Periods()
Private Sub Form_Load()
Periods = Array( _
"06:00 PM-07:00PM", _
"07:01 PM-08:00PM", _
"09:00 PM-10:00PM", _
"1AM-2AM" _
)
End Sub
Private Sub tmrSystemTime_Timer()
lblSystemTime.Caption = FormatDateTime(Now, vbLongTime)
Dim OnPeriod As Integer
OnPeriod = GetPeriod()
If OnPeriod < 0 Then
lblTimeLeft.Caption = vbNullString
lblTimePassed.Caption = vbNullString
lblPeriod.Caption = "Unknown Period"
Else
lblPeriod = CStr(OnPeriod + 1) & ". period"
lblTimeLeft.Caption = "Time Left: " & Format( _
DateAdd("s", _
DateDiff("s", _
CDate(lblSystemTime.Caption), _
CDate(Split(Periods(OnPeriod), "-")(1))), _
CDate("0") _
), _
"nn:ss" _
)
lblTimePassed.Caption = "Time Passed: " & Format( _
DateAdd("s", _
DateDiff("s", _
CDate(Split(Periods(OnPeriod), "-")(1)), _
CDate(lblSystemTime.Caption)), _
CDate("0") _
), _
"nn:ss" _
)
End If
End Sub
Private Function GetPeriod() As Integer
Dim ICount As Integer
For Each Pr In Periods
If CDate(Split(Pr, "-")(0)) <= CDate(lblSystemTime.Caption) And _
CDate(Split(Pr, "-")(1)) >= CDate(lblSystemTime.Caption) Then
GetPeriod = ICount
Exit Function
End If
ICount = ICount + 1
Next
GetPeriod = -1
End Function
答案 1 :(得分:1)
这可能有所帮助:
Private Sub TimeCheck(byval int_TimeNow as Integer)
dim intTimeThen as string 'set a variable to compare for the THEN time
dim intTimeNow as string 'set a variable to compare for the NOW time
dim intDiff as string ' set a variable for the difference in time
intTimeNow = int_TimeNow 'just to ensure we don't mess with any data
intTimeThen = val(txtTimeThen.text) 'get the numeric value of the time, the system will
'convert it from a string to the value here.
intDiff = intTimeThen - intTimeNow 'Do the math
lstTimeEvents.additem timevalue(intDiff) 'write it to a listbox
End Sub
我意识到这不是您正在使用的编码约定,但它应该在某种程度上展示您正在寻找的内容。