当我使用此代码时,我为users表中存储的每个id获取一条记录。相反,我希望每次只能插入1条记录,与记录的用户ID匹配。
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// escape variables for security
$acname = mysqli_real_escape_string($con, $_POST['ACName']);
$btu = mysqli_real_escape_string($con, $_POST['BTU']);
$space = mysqli_real_escape_string($con, $_POST['Space']);
$energyclass = mysqli_real_escape_string($con, $_POST['EnergyClass']);
$sql="INSERT INTO aircondition (id, ACName, BTU, Space, EnergyClass)
SELECT id, '$acname', '$btu', '$space', '$energyclass'
FROM users";
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
}
header('location:aircondition.php');
mysqli_close($con);
?>
答案 0 :(得分:0)
您的select语句中必须有where子句
$sql="INSERT INTO aircondition (id, ACName, BTU, Space, EnergyClass)
SELECT id, '$acname', '$btu', '$space', '$energyclass'
FROM users WHERE usernamecolumn= currentusername ;