Question

我遇到了一个问题，我的治疗记录包含6行数据，我即将到来的约会行只包含1行数据，但现在我的约会行也被复制成6行作为我的第一个表。

这里是mysql代码：

if(empty($_GET['name'])) {
   echo 'Please don\'t try to hack!<br /><a href="./" title="Retry">Click here to <b>retry</b> again</a>';
   exit;
}

require_once 'dbconnect.php';
$p_id = $_GET['name'];

try {
    $conn = new PDO("mysql:host=$host;dbname=$dbname", $username, $password);

    $sql = "SELECT *
            FROM appointment a
            LEFT JOIN customer c
            ON a.customer_id = c.cust_id
            AND a.deleted = '0'
            LEFT JOIN services s
            ON c.cust_id = s.customer_id
            AND s.deleted = '0'
            WHERE c.slug  LIKE :id";

$q = $conn->prepare($sql);
    $q->execute(array('id' => $p_id));
    $q->setFetchMode(PDO::FETCH_ASSOC);
    $cs = $q->fetchAll();

} catch (PDOException $pe) {
    die("Could not connect to the database $dbname :" . $pe->getMessage());

这是我的html视图代码：

<div id="container">
    <h1>Customer Record</h1>
    Name: <?php echo htmlspecialchars($cs[0]['fname'].' '.$cs[0]['lname']); ?> <br />
    Gender: <?php echo htmlspecialchars($cs[0]['gender']); ?> <br />
    Mobile Number: <?php echo htmlspecialchars($cs[0]['number']); ?> <br /><br />
    <table class="table table-bordered table-condensed">
        <thead>
            <tr>
                <th>Treatment</th>
                <th>Date</th>
                <th>Action</th>
            </tr>
        </thead>
        <tbody>
            <?php foreach($cs as $r):?>
            <tr>
                <td><?php if($r['treatment'] === NULL) { echo "No Record Found"; } else { echo htmlspecialchars($r['treatment']); } ?></td>
                <td><?php if($r['date'] === NULL) { echo "No Record Found"; } else { echo htmlspecialchars($r['date']); } ?></td>
                <td><?php if($r['service_id'] === NULL) { echo "No Record Found"; } else { ?><a href="editrecord.php?name=<?php echo htmlspecialchars($r['slug']) ?>&id=<?php echo htmlspecialchars($r['service_id']) ?>">Edit Record</a> or <a href="deleterecord.php?name=<?php echo htmlspecialchars($r['slug']) ?>&id=<?php echo htmlspecialchars($r['service_id']) ?>">Delete Record</a><?php } ?></td>
            </tr>
            <?php endforeach; ?>
        </tbody>
        <thead>
            <tr>
                <th>Upcoming Appointment</th>
                <th>Appointment Type</th>
                <th>Action</th>
            </tr>
        </thead>
        <tbody>
            <?php foreach($cs as $r):?>
            <tr>
                <td><?php if($r['appt_date'] === NULL) { echo "No Record Found"; } else { echo htmlspecialchars($r['appt_date']); } ?></td>
                <td><?php if($r['appointment_type'] === NULL) { echo "No Record Found"; } else { echo htmlspecialchars($r['appointment_type']); } ?></td>
                <td><?php if($r['service_id'] === NULL) { echo "No Record Found"; } else { ?><a href="editrecord.php?name=<?php echo htmlspecialchars($r['slug']) ?>&id=<?php echo htmlspecialchars($r['service_id']) ?>">Edit Record</a> or <a href="deleterecord.php?name=<?php echo htmlspecialchars($r['slug']) ?>&id=<?php echo htmlspecialchars($r['service_id']) ?>">Delete Record</a><?php } ?></td>
            </tr>
            <?php endforeach; ?>
        </tbody>
    </table>
        <a href="./">Seach Again</a><br /><br />
        <a href="addrecord.php?name=<?php echo htmlspecialchars($r['slug']) ?>">Add Record</a>

</div>

我不知道哪里出错了，但我怀疑我的sql代码部分出错了。

这是SQLFiddle for LEFT JOIN Appointment Table

以下是SQLFiddle for LEFT JOIN Appointment Table and LEFT JOIN Services Table

我需要这三个表数据来显示所有信息，如果我只使用来自约会表的左连接它显示6行没有重复错误，但如果我使用左连接约会表和左连接服务表，我的治疗表结果显示6行是正确的，但我的Upcoming Table也有6行相同的结果，而在数据库中只有1行数据。

请告知我哪里出错了。

第二个表的mysql结果与第一个表的行长度相同

0 个答案: