Question

import java.util.Scanner;
public class array1 {
    public static void main(String [] args){
        int table[][] = new int[5][5];
        Scanner scan = new Scanner(System.in);
        for(int i =0; i < 5; i++){
            for(int j =0; j < 5; j++){
                System.out.println("Write a value for row " +i + " column " +j);
                int n = scan.nextInt();
                table[i][j] = n;
            }
        }
        for(int i =0; i < 5; i++){
            for(int j =0; j < 5; j++){
                System.out.print(table[i][j] + "\t");
            }
            System.out.println();
        }

        int sum = 0;
        boolean prime = true;
        for(int i =0; i < 5; i++){
            for(int j =0; j < 5; j++){
                for(int e = 2; e < table[i][j]; e++ ){
                    if(table[i][j] % e == 0){
                        prime = false;
                    }
                }
                if(prime == true){
                    sum += table[i][j];
                }
                else{}
            }
        }
        System.out.println();
        System.out.println("Sum of all prime numbers in this array is " +sum);
    }
}

好吧，正如标题本身所说的那样，程序应该总结用户定义的数组表中的所有素数，但它只是总结第一行。我检查了所有括号，没有任何帮助。任何帮助，将不胜感激！谢谢！

Answer 1

您应该为每次迭代重置素数：

for (int i = 0; i < 5; i++) {
    for (int j = 0; j < 5; j++) {
        for (int e = 2; e < table[i][j]; e++) {
            if (table[i][j] % e == 0) {
                        prime = false;
            }
        }
        if (prime == true) {
            sum += table[i][j];
        } else {
        }
        prime = true;
    }
}

双维数组（Prime（sum）计数缺陷）

1 个答案: