Question

我正在尝试使用spring boot，gradle和tomcat实现一个基本的hello world web应用程序。我有以下java类。当我执行“./gradlew clean tomcatRunWar”tomcat刚刚启动但无法访问时。

可能是什么问题？

的build.gradle

buildscript {
    repositories {
        mavenLocal()
        mavenCentral()
    }
    dependencies {
        classpath 'org.gradle.api.plugins:gradle-tomcat-plugin:0.9.8'
        classpath 'org.springframework.boot:spring-boot-gradle-plugin:1.1.6.RELEASE'
    }
}

apply plugin: 'java'
apply plugin: 'eclipse-wtp'
apply plugin: 'idea'
apply plugin: 'spring-boot'
apply plugin: 'war'
apply plugin: 'tomcat'

mainClassName = "au.com.aeas.config.WebAppInitializer"

war {
    baseName = ''
    version =  '0.0.0'
}

repositories {
    mavenLocal()
    mavenCentral()
}

configurations {
    providedRuntime
}

dependencies {
    tomcat "org.apache.tomcat.embed:tomcat-embed-core:7.0.42",
        "org.apache.tomcat.embed:tomcat-embed-logging-juli:7.0.42"
    tomcat("org.apache.tomcat.embed:tomcat-embed-jasper:7.0.42") {
        exclude group: 'org.eclipse.jdt.core.compiler', module: 'ecj'
    }

    compile 'org.springframework.security:spring-security-config:3.2.5.RELEASE'
    compile 'org.springframework.security:spring-security-web:3.2.5.RELEASE'
    compile("org.springframework.boot:spring-boot-starter-web:1.1.6.RELEASE")
    providedRuntime("org.springframework.boot:spring-boot-starter-tomcat:1.1.6.RELEASE")
}

task wrapper(type: Wrapper) { gradleVersion = '1.6' }

WebAppInitializer.java

  @EnableAutoConfiguration
  @ComponentScan("au.com.aeas.web.controller")
  @Controller
  public class WebAppInitializer extends WebMvcConfigurerAdapter {

  public static void main(String[] args) throws Exception {
     new SpringApplicationBuilder(WebAppInitializer.class).run(args);
  }

  @Bean
  public ApplicationSecurity applicationSecurity() {
     return new ApplicationSecurity();
  }

  @Bean
  public InternalResourceViewResolver viewResolver() {
     InternalResourceViewResolver internalResourceViewResolver = new InternalResourceViewResolver();
     internalResourceViewResolver.setPrefix("WEB-INF/views/");
     internalResourceViewResolver.setSuffix(".jsp");
     return internalResourceViewResolver;
  }

  @Bean
  public AuthenticationSecurity authenticationSecurity() {
     return new AuthenticationSecurity();
  }

  @Order(SecurityProperties.ACCESS_OVERRIDE_ORDER)
  protected static class ApplicationSecurity extends
    WebSecurityConfigurerAdapter {

    @Autowired
    private SecurityProperties security;

    @Override
    protected void configure(HttpSecurity http) throws Exception {
         http.authorizeRequests().anyRequest().fullyAuthenticated().and()
            .formLogin();
    }
  }

  @Order(Ordered.HIGHEST_PRECEDENCE + 10)
  protected static class AuthenticationSecurity extends
    GlobalAuthenticationConfigurerAdapter {

  @Override
  public void init(AuthenticationManagerBuilder auth) throws Exception {
       auth.inMemoryAuthentication().withUser("user").password("password")
            .roles("USER");
   }
  }
 }

HelloController.java

@Controller
public class HelloController {

  @RequestMapping(value = "/hello", method = RequestMethod.GET)
  public ModelAndView hello() {
    ModelAndView modelAndView = new ModelAndView();
    modelAndView.addObject("message", "charith");
    modelAndView.setViewName("hello");
    return modelAndView;
  }

}

的hello.jsp

<html>
<head>
  <title>Hello world page</title>
</head>
<body>
   <h1>${message}</h1>
</body>
</html>

Answer 1

我没有在任何地方看到ServletContextInitializer，所以我的猜测是gradle bootRun（或运行你的主要方法）可行，但部署到Tomcat不会。基本ServletContextInitializer易于编写且记录良好（例如：https://spring.io/guides/gs/convert-jar-to-war-maven/）。例如：

public class WebInitializer extends SpringBootServletInitializer {
  @Override
  protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
    return application.sources(WebAppIninitializer.class);
  }
}

Answer 2

如果您尝试在tomcat上运行它，那么为什么不将它打包到jar文件中并使用嵌入式tomcat？当然，您必须稍微更改一个项目结构。

Spring boot + gradle + tomcat你好世界应用程序无法正常工作

2 个答案: