Question

我想向NSURLRequest添加2个参数。有没有办法或者我应该使用AFnetworking？

Answer 1

如果您使用AFNetworking，可能会更容易。如果您有自己想做的事情，可以使用NSURLSession，但必须编写更多代码。

如果您使用AFNetworking，它会处理序列化请求，区分成功和错误等所有这些细节：

NSDictionary *params = @{@"firstname": @"John", @"lastname": @"Doe"};

AFHTTPSessionManager *manager = [AFHTTPSessionManager manager];
[manager POST:urlString parameters:params success:^(NSURLSessionDataTask *task, id responseObject) {
    NSLog(@"responseObject = %@", responseObject);
} failure:^(NSURLSessionDataTask *task, NSError *error) {
    NSLog(@"error = %@", error);
}];

这假定服务器的响应是JSON。如果不是（例如，如果是纯文本或HTML），则可以在POST之前加上：

manager.responseSerializer = [AFHTTPResponseSerializer serializer];

如果使用NSURLSession自行完成，您可以像这样构建请求：

NSDictionary *params = @{@"firstname": @"John", @"lastname": @"Doe"};

NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:[self httpBodyForParameters:params]];

您现在可以使用NSURLSession发起请求。例如，您可以这样做：

NSURLSessionTask *task = [[NSURLSession sharedSession] dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
    if (error) {
        NSLog(@"dataTaskWithRequest error: %@", error);
    }

    if ([response isKindOfClass:[NSHTTPURLResponse class]]) {
        NSInteger statusCode = [(NSHTTPURLResponse *)response statusCode];
        if (statusCode != 200) {
            NSLog(@"Expected responseCode == 200; received %ld", (long)statusCode);
        }
    }

    // If response was JSON (hopefully you designed web service that returns JSON!),
    // you might parse it like so:
    //
    // NSError *parseError;
    // id responseObject = [NSJSONSerialization JSONObjectWithData:data options:0 error:&parseError];
    // if (!responseObject) {
    //     NSLog(@"JSON parse error: %@", parseError);
    // } else {
    //     NSLog(@"responseObject = %@", responseObject);
    // }

    // if response was text/html, you might convert it to a string like so:
    //
    // NSString *responseString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
    // NSLog(@"responseString = %@", responseString);
}];
[task resume];

其中

/** Build the body of a `application/x-www-form-urlencoded` request from a dictionary of keys and string values

 @param parameters The dictionary of parameters.
 @return The `application/x-www-form-urlencoded` body of the form `key1=value1&key2=value2`
 */
- (NSData *)httpBodyForParameters:(NSDictionary *)parameters {
    NSMutableArray *parameterArray = [NSMutableArray array];

    [parameters enumerateKeysAndObjectsUsingBlock:^(NSString *key, NSString *obj, BOOL *stop) {
        NSString *param = [NSString stringWithFormat:@"%@=%@", [self percentEscapeString:key], [self percentEscapeString:obj]];
        [parameterArray addObject:param];
    }];

    NSString *string = [parameterArray componentsJoinedByString:@"&"];

    return [string dataUsingEncoding:NSUTF8StringEncoding];
}

和

/** Percent escapes values to be added to a URL query as specified in RFC 3986.

 See http://www.ietf.org/rfc/rfc3986.txt

 @param string The string to be escaped.
 @return The escaped string.
 */
- (NSString *)percentEscapeString:(NSString *)string {
    NSCharacterSet *allowed = [NSCharacterSet characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789-._~"];
    return [string stringByAddingPercentEncodingWithAllowedCharacters:allowed];
}

Answer 2

NSDictionary *params = @{@"firstname": @"John", @"lastname": @"Doe"};
NSMutableString *str = [NSMutableString stringWithString:@"http://yoururl.com/postname?"];
NSArray *keys = [params allKeys];
NSInteger counter = 0;
for (NSString *key in keys) {
    [str appendString:key];
    [str appendString:@"="];
    [str appendString:params[key]];
    if (++counter < keys.count) { // more params to come...
        [str appendString:@"&"];
    }
}
NSURL *url = [NSURL URLWithString:str];
// should give you: http://yoururl.com/postname?firstname=John&lastname=Doe
// not tested, though

如何使用2个参数进行POST NSURLRequest？

2 个答案: