Question

电话号码是这样的。电话ABMultiValueRef 0x17674380有1个值 0： $ !! $ （0x176740e0） - 7124779070（0x176742a0）

如何从上面一行获得此号码“ 7124779070 ”。

我正在使用此代码用于ios 7.这是正确还是错误，请建议我。

 int i;
    ABAddressBookRef contactBook = ABAddressBookCreateWithOptions(NULL, NULL);
    NSMutableArray *allData = ( NSMutableArray *)(ABAddressBookCopyArrayOfAllPeople(contactBook));
    CFIndex contactNum = CFArrayGetCount((__bridge CFArrayRef)(allData));

    for (i = 0; i < contactNum; i++)
    {
        ABRecordRef ref = CFArrayGetValueAtIndex((__bridge CFMutableArrayRef)(allData), i);
        NSString*  firstName = ABRecordCopyValue(ref, kABPersonFirstNameProperty);
        NSString* lastName = ABRecordCopyValue(ref, kABPersonLastNameProperty);
        NSString*  phonesNum = ABRecordCopyValue(ref, kABPersonPhoneProperty);

        // Remove all formatting symbols that might be in both phone number being compared
        NSCharacterSet *toExclude = [NSCharacterSet characterSetWithCharactersInString:@"/.()- "];
        phonesNum = [[phonesNum componentsSeparatedByCharactersInSet:toExclude] componentsJoinedByString: @""];
    NSString *phoneNumber = [[phonesNum componentsSeparatedByCharactersInSet:toExclude] componentsJoinedByString: @""];



        NSMutableDictionary *dic = [[NSMutableDictionary alloc] init];
        if (firstName!=nil)
        {
            [dic setObject:(__bridge id)(firstName) forKey:@"firstName"];

        }
        if (lastName !=nil) {
            [dic setObject:(__bridge id)(lastName) forKey:@"lastName"];

        }
        if (phonesNum!=nil) {
            [dic setObject:(__bridge id)(phonesNum) forKey:@"phonesNum"];
        }

        [arr_Contacts addObject:dic];

        NSLog(@"First name %@", firstName);
        NSLog(@"Last Name %@", lastName);
        NSLog(@"Phone %@", phonesNum);
    }

Answer 1

首先，请求权限：

ABAuthorizationStatus status = ABAddressBookGetAuthorizationStatus();

if (status != kABAuthorizationStatusAuthorized && status != kABAuthorizationStatusNotDetermined) {
    // tell user to enable contacts in privacy settings
    NSLog(@"You previously denied access: You must enable access to contacts in settings");

    return;
}

CFErrorRef error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);
if (!addressBook) {
    NSLog(@"ABAddressBookCreateWithOptions error: %@", CFBridgingRelease(error));
    return;
}

ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
    if (error) {
        NSLog(@"ABAddressBookRequestAccessWithCompletion error: %@", CFBridgingRelease(error));
    }

    if (granted) {
        [self getContacts:addressBook];
    } else {
        // tell user to enable contacts in privacy settings
        NSLog(@"You just denied access: You must enable access to contacts in settings");
    }

    CFRelease(addressBook);
});

其次，要检索电话号码，请使用ABMultiValueCopyValueAtIndex：

- (void)getContacts:(ABAddressBookRef)addressBook
{
    NSArray *allData = CFBridgingRelease(ABAddressBookCopyArrayOfAllPeople(addressBook));
    NSInteger contactCount = [allData count];

    for (int i = 0; i < contactCount; i++) {
        ABRecordRef person = CFArrayGetValueAtIndex((__bridge CFArrayRef)allData, i);

        NSString *firstName = CFBridgingRelease(ABRecordCopyValue(person, kABPersonFirstNameProperty));
        NSString *lastName  = CFBridgingRelease(ABRecordCopyValue(person, kABPersonLastNameProperty));

        NSMutableDictionary *dictionary = [NSMutableDictionary dictionary];
        if (firstName) {
            dictionary[@"firstName"] = firstName;
        }
        if (lastName) {
            dictionary[@"lastName"]  = lastName;
        }

        ABMultiValueRef phones = ABRecordCopyValue(person, kABPersonPhoneProperty);
        CFIndex phoneNumberCount = ABMultiValueGetCount(phones);

        if (phoneNumberCount > 0) {
            NSString *phone = CFBridgingRelease(ABMultiValueCopyValueAtIndex(phones, 0));
            dictionary[@"phone"] = phone;
        }

        // or if you wanted to iterate through all of them, you could do something like:
        //
        // for (int j = 0; j < phoneNumberCount; j++) {
        //      NSString *phone = CFBridgingRelease(ABMultiValueCopyValueAtIndex(phones, j));
        //
        //     // do something with `phone`
        // }

        if (phones) {
            CFRelease(phones);
        }

        [arr_Contacts addObject:dictionary];
    }
}

上面提到的一些其他问题：

ABAddressBookCreateWithOptions不返回可变数组。这是一个不可变的数组。用不可变的替换所有这些可变引用。
您必须尊重Create Rule，即您负责释放从Core Foundation方法返回的任何对象，其名称中包含Create或Copy。如果对象支持免费桥接（例如，联系人数组，名字字符串，姓氏字符串等），则可以使用CFBridgingRelease或__bridge_transfer将所有权转移到ARC。如果对象不支持免费桥接（例如上面的phones或addressBook对象），则必须为相关对象显式调用CFRelease。

确保通过静态分析器运行代码（ shift + 命令 + B ，或从Xcode的“产品”中选择“分析” “菜单”，它将为您识别这些问题。
如果某个函数（例如ABAddressBookCreateWithOptions提供了错误参数），您应该利用它。我说明了上面CFErrorRef对象的正确使用。

Answer 2

你在Phone％@ NSLog的控制台中听到了什么？如果电话ABMultiValueRef 0x17674380有1个值0：$ !! $（0x176740e0） - 7124779070（0x176742a0）只是' - '后面的子串

NSString *myString = @"Phone ABMultiValueRef 0x17674380 with 1 value(s) 0: $!!$ (0x176740e0) - 7124779070 (0x176742a0)";
NSArray *myArray = [myString componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:@"-"]];

这是我获取手机的方法

   - (void) getContacts
    {
    NSMutableDictionary *response = [[NSMutableDictionary alloc] init];

    ABAddressBookRef contactBook = ABAddressBookCreateWithOptions(NULL, NULL);
    arr_Contacts = [[NSMutableArray alloc] init];
    ABAddressBookRef allPeople = contactBook;
    CFArrayRef allContacts = ABAddressBookCopyArrayOfAllPeople(allPeople);
    CFIndex numberOfContacts  = ABAddressBookGetPersonCount(allPeople);
    NSLog(@"contact == %@",allContacts);


    NSLog(@"numberOfContacts------------------------------------%ld",numberOfContacts);

    for(int i = 0; i < numberOfContacts; i++){
        NSString* name = @"";
        NSString* phone = @"";
        NSString* email = @"";

        ABRecordRef aPerson = CFArrayGetValueAtIndex(allContacts, i);
        ABMultiValueRef fnameProperty = ABRecordCopyValue(aPerson, kABPersonFirstNameProperty);
        ABMultiValueRef lnameProperty = ABRecordCopyValue(aPerson, kABPersonLastNameProperty);

        ABMultiValueRef phoneProperty = ABRecordCopyValue(aPerson, kABPersonPhoneProperty);\
        ABMultiValueRef emailProperty = ABRecordCopyValue(aPerson, kABPersonEmailProperty);

        NSArray *emailArray = (__bridge NSArray *)ABMultiValueCopyArrayOfAllValues(emailProperty);
        NSArray *phoneArray = (__bridge NSArray *)ABMultiValueCopyArrayOfAllValues(phoneProperty);


        if (fnameProperty != nil) {
            name = [NSString stringWithFormat:@"%@", fnameProperty];
        }
        if (lnameProperty != nil) {
            name = [name stringByAppendingString:[NSString stringWithFormat:@" %@", lnameProperty]];
        }

        if ([phoneArray count] > 0) {
            if ([phoneArray count] > 1) {
                for (int i = 0; i < [phoneArray count]; i++) {
                    phone = [phone stringByAppendingString:[NSString stringWithFormat:@"%@, ", [phoneArray objectAtIndex:i]]];
                }
            }else {
                phone = [NSString stringWithFormat:@"%@", [phoneArray objectAtIndex:0]];
            }
        }

        if ([emailArray count] > 0) {
            if ([emailArray count] > 1) {
                for (int i = 0; i < [emailArray count]; i++) {
                    email = [email stringByAppendingString:[NSString stringWithFormat:@"%@\n", [emailArray objectAtIndex:i]]];
                }
            }else {
                email = [NSString stringWithFormat:@"%@", [emailArray objectAtIndex:0]];
            }
        }
        NSLog(@"NAME : %@",name);
        NSLog(@"PHONE: %@",phone);
        NSLog(@"EMAIL: %@",email);
        NSLog(@"\n");
        [response setObject:name forKey:@"name"];
        [response setObject:phone forKey:@"phone"];
        [response setObject:email forKey:@"email"];

      [arr_Contacts addObject:response];
    }

    }

干杯

IOS ::如何从ABAddressBook获取联系号码

2 个答案: