Question

我真的不知道自己做错了什么。代码只是不会写在表中

if (isset($_POST['submit']))
        {
            // get the form data
            $name = htmlentities($_POST['name'], ENT_QUOTES);
            $last = htmlentities($_POST['last'], ENT_QUOTES);
            $date = htmlentities($_POST['date'], ENT_QUOTES);
            $ran = htmlentities($_POST['ran'], ENT_QUOTES);

            if ($name == '' || $last == '' || $date == '' || $ran == '')
            {
                // if they are empty, show an error message and display the form
                $error = 'ERROR: Please fill in all required fields!';
                renderForm($name, $last, $date, $ran, $error);
            }
            else
            {
                // insert the new record into the database
                if ($stmt = $mysqli->prepare("INSERT users (name, last, date, ran) VALUES (?, ?, ?, ?)"))
                {
                    $stmt->bind_param("ssss", $name, $last, $date, $ran);
                    $stmt->execute();
                    $stmt->close();
                }
                // show an error if the query has an error
                else
                {
                    echo "ERROR: Could not prepare SQL statement.";
                }

                // redirec the user
                header("Location: view.php");
            }

        }
        // if the form hasn't been submitted yet, show the form
        else
        {
            renderForm();
        }

    // close the mysqli connection
    $mysqli->close();
?>

我已准备好表格，如果我手动插入表格，它可以正常工作（我有一个View.php）但是当我运行表单时没有任何错误，没有错误！

Answer 1

修正了它：

$stmt = $mysqli->prepare("INSERT INTO users (`name`,`last`,`date`,`ran`) VALUES (?, ?, ?, ?)");

Mysqli和绑定多个值

1 个答案: