Question

可以将字体颜色应用于单个单元格，而无需创建样式：

Axlsx::Package.new do |p|
  p.workbook.add_worksheet(:name => "test") do |ws|        
    ws.add_row ["a", "b", "c"]
    ws.add_row ["d", "e", "f"]
    ws.add_row ["g", "h", "i"]

    ws.rows.each do |r|
        r.cells.each do |c|
            c.color = "009900"
            if ['a', 'e', 'i'].include?(c.value)
              c.color = "009900" // how can I do the same for background color?
            end
        end
    end
  end
  p.serialize('test.xlsx')
end

可以将样式应用于单个单元格：

Axlsx::Package.new do |p|
 p.workbook.add_worksheet(:name => "test") do |ws|
    style1 = ws.styles.add_style( :bg_color => "FFFFFF00")
    ws.add_row ["a", "b", "c"]
    ws.add_row ["d", "e", "f"]
    ws.add_row ["g", "h", "i"]

    ws.rows.each do |r|
        r.cells.each do |c|       
            if ['a', 'e', 'i'].include?(c.value)
              c.style = style1
            end
        end
    end
  end
  p.serialize('test.xlsx')
end

但在我的情况下这是不切实际的，因为我希望单元格背景是单元格值的函数，并且希望避免构建数百或数千种样式。

有什么建议吗？

Answer 1

我会在一个代码块本身回答你的问题，为特定单元格添加样式并为单元格添加背景颜色，你可以这样做：

Axlsx::Package.new do |p|
    p.workbook.add_worksheet(:name => "test") do |ws|
        style1 = ws.styles.add_style(:bg_color => "EF0920", :fg_color => "FFFFFF")
        ws.add_row ["a", "b", "c"], :style => style1
        ws.add_row ["d", "e", "f"], :bg_color 
    end
    p.serialize('test.xlsx')
end

请注意： bg_color是背景颜色 fg_color是前景色（文本颜色）。

Answer 2

您可以在更改模式下为行和单元格添加样式，您可以使用所需的行准备好工作表。这种方式可能过于静态，您必须对所有行和单元格详细信息进行硬编码。

package = Axlsx::Package.new
package.workbook.add_worksheet(name: 'Worksheet') do |sheet|
    # after adding required rows
    style1 = sheet.styles.add_style(:bg_color => "EF0920", :fg_color => "FFFFFF")
    sheet.rows[6].cells[1].style = style1
end

Axlsx gem：是否可以将背景颜色应用于单个细胞？

2 个答案: