Question

这是Sam.Currently我在我的应用程序中开发了twitter。我需要在没有ComposeController的情况下实现它。我需要从社交框架集成SLRequest。我使用的代码如下

ACAccountStore *accountStore = [[ACAccountStore alloc] init];
ACAccountType *twitterAccountType =[accountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
[accountStore requestAccessToAccountsWithType:twitterAccountType options:NULL completion:^(BOOL granted, NSError *error) {
    if (granted) {
        NSLog(@"Creating Request");
        //  Step 2:  Create a request
        NSArray *twitterAccounts =[accountStore accountsWithAccountType:twitterAccountType];
        NSURL *url = [NSURL URLWithString:@"https://api.twitter.com/1.0/statuses/update.json"];
        NSDictionary *params = @{@"screen_name" : @"naheshsamy",@"include_rts" : @"0",@"trim_user" : @"1",@"count" : @"1"};
        SLRequest *request =
        [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodGET URL:url parameters:params];

        //  Attach an account to the request
        [request setAccount:[twitterAccounts lastObject]];
        NSLog(@"Request %@",request);
        //  Step 3:  Execute the request
        [request performRequestWithHandler: ^(NSData *responseData,NSHTTPURLResponse *urlResponse,NSError *error) {
            if (responseData) {
                if (urlResponse.statusCode >= 200 && urlResponse.statusCode < 300) {
                    NSError *jsonError;
                    NSDictionary *timelineData = [NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingAllowFragments error:&jsonError];

                    if (timelineData) {
                        NSLog(@"Timeline Response: %@\n", timelineData);
                    }
                    else {
                        // Our JSON deserialization went awry
                        NSLog(@"JSON Error: %@", [jsonError localizedDescription]);
                    }
                }
                else {
                    // The server did not respond ... were we rate-limited?
                    NSLog(@"The response status code is %d %@ %@",urlResponse.statusCode,urlResponse.suggestedFilename,error);
                }
            }
        }];
    }
    else {
        // Access was not granted, or an error occurred
        NSLog(@"%@", [error localizedDescription]);
    }
}];

我总是收到状态400错误.. 任何帮助将不胜感激。问候， Sam.P

Answer 1

代码看起来与我使用的类似。他们确实警告说，不再支持API的1.0版本，并且可能无法运行。尝试更改为1.1并查看它是否解决了您的问题。

@"https://api.twitter.com/1.1/statuses/update.json"

Twitter与SLRequest共享

1 个答案: