Question

*新手道歉......

以下代码：

dates = ['Transaction_Date','Renewal_Date']
dateoptions = ['Year','Month','Date']
word1 = "Amount"

dates.each do |x|
  puts word1 + " by " + x
  end

返回

Amount by Transaction_Date
Amount by Renewal_Date

我希望结果是日期和日期选项的串联，如此

Amount by Transaction_Date (Year)
Amount by Transaction_Date (Month)
Amount by Transaction_Date (Date)
Amount by Renewal_Date (Year)
Amount by Renewal_Date (Month)
Amount by Renewal_Date (Month)

我正在考虑做一个嵌套的“每个做”，但我仍然不知道如何处理两个数组的连接。

感谢您的输入

Answer 1

您需要使用嵌套的each：

dates = ['Transaction_Date','Renewal_Date']
dateoptions = ['Year','Month','Date']
word1 = "Amount"

dates.each do |d|
  dateoptions.each do |option|
    puts "#{word1} by #{d} (#{option})"
  end
end

或者您可以使用Array#product

dates.product(dateoptions) do |d, option|
  puts "#{word1} by #{d} (#{option})"
end

Answer 2

您可以使用Array#product方法：

dates.product(dateoptions).each do |date, option|
  puts "#{word1} by #{date} (#{option})"
end

Answer 3

dates = ['Transaction_Date','Renewal_Date']
dateoptions = ['Year','Month','Date']
word1 = "Amount"

dates.each do |x|
  dateoptions.each do |y|
    puts "#{word1} by #{x} (#{y})"
  end
end

Answer 4

2.1.2 :009 > dates.each do |e|
2.1.2 :010 >     dateoptions.each do |o|
2.1.2 :011 >       puts "#{word1} by #{e} (#{o})"
2.1.2 :012?>     end
2.1.2 :013?>   end
Amount by Transaction_Date (Year)
Amount by Transaction_Date (Month)
Amount by Transaction_Date (Date)
Amount by Renewal_Date (Year)
Amount by Renewal_Date (Month)
Amount by Renewal_Date (Date)

Ruby嵌套每个do +数组连接

4 个答案: