Question

所以即时通讯正在处理一个项目。我不是Python的专家，也不是编码方面的白痴。这个问题可能有一个非常简单的答案，但我似乎无法做到正确。我的整个代码要求用户使用列表中的随机选择来回答问题。

    import turtle
import random
turtle.speed("fastest")


pi = 3
minNumber = 5
maxNumber = 10
score = 0
listNmbers = []

a = [1,3,5,7,9]

red = random.random()
green = random.random()
blue = random.random()

num1 = random.choice(a)


def drawSquare():
    for i in range(4):
        turtle.begin_fill()
        turtle.pendown()
        turtle.forward(50)
        turtle.left(90)
        turtle.end_fill()
    turtle.right(360/userAnswer)


turtle.penup()
turtle.setpos(-700,-200)
turtle.fillcolor("green")

print("Welcome! What is your name??")
name = str(input())

print("Hello", name,"you need to calculate the circumference of a circle when given a      diameter. To calculate the circumference, use the equasion; Pi x Diameter (Pi = 3")
num = input("how many questions would you like to answer? (Pick between 5 and 10)")

def getNumbers(numbers):

    try:
        badInput = False
        while not (badInput):
            num = input("how many questions would you like to answer? (Pick between 5 and 10)")
            numbers = int(num)
            badInput = (numbers >= 4) or (numbers >= maxNumber)
            if badInput == False:
                print ("Please input an integer between 5 and 10 please")
                badInput = False
    except:
        print("Please input an integer between 5 and 10")
        numbers= 0;
        numbers = getNumbers(numbers)

numbers= 0;
numbers = getNumbers(numbers)    

for i in range(int(num)):
    red = random.random()
    green = random.random()
    blue = random.random()
    num1 = random.choice(a)
    turtle.color(red,green,blue)
    correct = num1 * 3

    print("What is the cirumference of the circle if", num1,"is the diameter and Pi is 3?")
    userAnswer = int(input())
    if userAnswer == correct:
        print("That's Correct! Well Done")
        score = score + 1

        for k in range(correct):
            turtle.color(red,green,blue)
            drawSquare()

        turtle.penup()
        turtle.forward(150)


    else:
        print("sorry thats is incorrect")

在这段代码中，它询问用户他们想要问多少问题（作为整数）。当给出参数中的数字时，我的代码运行良好，但是一旦给出诸如19的数字，它就会在不应该的情况下继续。此外，如果给出了一个字符串，它会运行良好并再次询问一个整数，但如果在被询问后给出一个整数，它就会崩溃。错误读取：

for i in range(int(num)):`ValueError: invalid literal for int() with base 10: 'test'`

所有帮助都会非常感激。谢谢大家

Answer 1

你在一般的try..except中隐藏了太多代码（尝试按Ctrl + C，同时输入是必需的......不！）。我会以这种方式写这个函数：

def getNumbers():

    num = input("how many questions would you like to answer? (Pick between 5 and 10)")
    try:
        number = int(num)
    except:
        print("Not a number!")
        return getNumbers()

    goodInput = minNumber < number < maxNumber

    if not goodInput:
        print ("Please input an integer between 5 and 10 please")
        return getNumbers()
    else:
        return number

number = getNumbers()

Answer 2

getNumbers()不会返回任何值。因此，它隐式返回None，您在此处指定numbers：

numbers = getNumbers(numbers)

确保无论何时退出getNumbers()功能，都会返回numbers（可能在最后：

def getNumbers(numbers):

   ....

   return numbers

Answer 3

编辑：@see xbello回答有一个合适的答案。我的“中毒”代码没有按预期工作;）

首先，我必须说你的代码并不是很好阅读......但是这里有一些应该可以解决的问题

maxNumber = 10

print("Hello", name,"you need to calculate the circumference of a circle when given a      diameter. To calculate the circumference, use the equasion; Pi x Diameter (Pi = 3")
num = input("how many questions would you like to answer? (Pick between 5 and 10)")

def getNumbers(numbers):
    try:
        goodInput = False
        while not (goodInput):
            num = input("how many questions would you like to answer? (Pick between 5 and 10)")
            numbers = int(num)

            # Here was a bad condition having a look at your comments
            goodInput = (numbers > 4) and (numbers <= maxNumber)

            if goodInput == False:
                print ("Please input an integer between 5 and 10 please")
                # goodInput is already False, no need to set it again

        # Here is the missing return
        return numbers
    except:
        print("Please input an integer between 5 and 10")
        numbers= 0;
        numbers = getNumbers(numbers)

numbers= 0;
numbers = getNumbers(numbers)    

for i in range(numbers):
    #Do stuff

你可以看到我为你的函数添加了一个返回值（默认情况下返回None），然后我将这个返回值推送到“数字”中。然后可以将“数字”值推送到range（）函数中以形成一个很好的for循环。

Python尝试除了问题

3 个答案: