Question

如何计算所有输入的整数而不计算0？

我想要的是如果用户输入0然后输出将是＆＃34;除了0＆＃34;之外没有输入任何数字，但由于我有其他输出它也将打印出来。

    Scanner input = new Scanner(System.in); 
    System.out.print("Enter integers, input ends with 0: "); 
    int number = input.nextInt(); 

    if(number==0){ //This prints out along with the other system.out.println
    System.out.println("No numbers were entered except 0");
    }

    while(number!=0){ 
    count++; 
    total += number; 

    if(number > 0){ 
    positive++; 
    } 
    else{ 
    negative++; 
    } 
    number = input.nextInt(); 
    } 
    average = total*1.0/count; 

    System.out.println("The number of positives is " + positive); 
    System.out.println("The number of negatives is " + negative); 
    System.out.println("The total count is " + total); 
    System.out.printf("The average is " + average); 
      } 
       }

    OUTPUT:
    Enter integers, input ends with 0: 1 2 -1 3 0
    The number of positives is 3
    The number of negatives is 1
    The total count is 4 //mine is reading out 5 entered integers instead of 4
    The average is 1.25`

     //0 is the only entered number
     Enter integers, input ends with 0: 0
     No numbers were entered except 0

Answer 1

您似乎期待与您所要求的不同的东西：

The total count is 4这反映了您输入的值的总和，而不是值的数量

使用System.out.println("The total count is " + count);可以获得值的数量（计数）。

要在未输入数字（0除外）时删除额外输出，请更改以下代码：

 System.out.println("The number of positives is " + positive); 
 System.out.println("The number of negatives is " + negative); 
 System.out.println("The total count is " + total); 
 System.out.printf("The average is " + average);

到

if (count > 0)
{
    System.out.println("The number of positives is " + positive); 
    System.out.println("The number of negatives is " + negative); 
    System.out.println("The total count is " + total); 
    System.out.printf("The average is " + average); 
}

如何计算输入的整数除0？

1 个答案: