Question

我得到总和，平均值和产品。我面临的真正困难是最小和最大的数字。

我可以用两个数字来做，但是三个数字对我没有任何意义。问我，我的问题是否清楚或者是否有意义。

import java.util.Scanner;

// exercise 2.17
public class ArithmeticSmallestLargest {

    public static void main(String[] args) {

        Scanner input = new Scanner(System.in);

        int num1;
        int num2;
        int num3;
        int sum;
        int average;
        int product;
        double largest

        System.out.print("Enter First Integer: ");
        num1 = input.nextInt();

        System.out.print("Enter Second Integer: ");
        num2 = input.nextInt();

        System.out.print("Enter Third Integer: ");
        num3 = input.nextInt();

        sum = num1 + num2 + num3;
        average = sum / 3;
        product = num1 * num2 * num3;


        if (largest =num1 > num2 & num2 > num3)

        System.out.println(sum);

        System.out.println(average);

        System.out.println(product);

        System.out.println("The biggest number is " + largest);
    }
}

Answer 1

import java.util.Scanner;

// exercise 2.17
public class ArithmeticSmallestLargest {

    public static void main(String[] args) {

        Scanner input = new Scanner(System.in);

        int num1;
        int num2;
        int num3;
        int sum;
        int average;
        int product;
        int largest;
        int smallest;

        System.out.print("Enter First Integer: ");
        num1 = input.nextInt();

        System.out.print("Enter Second Integer: ");
        num2 = input.nextInt();

        System.out.print("Enter Third Integer: ");
        num3 = input.nextInt();

        sum = num1 + num2 + num3;
        average = sum / 3;
        product = num1 * num2 * num3;

        largest = num1;
        smallest = num1;

        if(num2 > largest)
            largest = num2;

        if(num3 > largest)
            largest = num3;

        if(num2 < smallest)
            smallest = num2;

        if (num3 < smallest)
            smallest = num3;

        System.out.println("The sum is " + sum);

        System.out.println("The average is " + average);

        System.out.println("The product is " + product);

        System.out.println("Largest of three integers is " + largest + " and the smallest is "+ smallest + ".");
    }
}

Answer 2

for element1 in list_of_elements:
    for element2 in list_of_elements:
        if not element1 == element2:
             #do

Answer 3

import java.util.Scanner;

public class ArithmeticSmallestLargest {

    public static void main(String[] args) {

        Scanner input = new Scanner(System.in);

        int num1;
        int num2;
        int num3;
        int sum;
        int average;
        int product;
        int largest;
        int smallest;

        System.out.print("Enter First Integer: ");

        num1 = input.nextInt();

        System.out.print("Enter Second Integer: ");
        num2 = input.nextInt();

        System.out.print("Enter Third Integer: ");
        num3 = input.nextInt();

        sum = num1 + num2 + num3;
        average = sum / 3;
        product = num1 * num2 * num3;
        largest = num1;
        smallest = num1;

        if(num2 > largest)
            largest = num2;

        if(num3 > largest)
            largest = num3;

        if(num2 < smallest)
            smallest = num2;

        if (num3 < smallest)
            smallest = num3;

        System.out.printf("The sum is %d%n " ,  sum);

        System.out.printf("The average is %d%n " ,  average);

        System.out.printf("The product is %d%n " , product);

        System.out.printf("Largest of three integers is %d%n " , largest);  

        System.out.printf("Smallest of three integers is %d%n " , smallest);
    }
}

答案如下：

输入第一整数：60
输入第二个整数：90
输入第三整数：30

总和是180
平均是60
产品是162000
三个整数最大为90
三个整数中最小的是30

...程序退出代码为0
按ENTER退出控制台。

编写一个从用户输入三个整数的应用程序，并显示数字的总和，平均值，乘积，最小值和最大值

3 个答案: