Question

我有一个表名视频

表视频

id  name   upload_date

1   one     1408336348
2   two     1409884215

现在我想要选择所有数据，还要计算过去2天之间上传的视频，然后是是或否

结果如

 id  name   upload_date   new

1   one     1408336348    no
2   two     1409884215    yes

我正在使用此查询但无法正常工作

SELECT v.*,( if(from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY) then 'no' else 'yes') 
 AS new FROM `video` as v

查询返回错误

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') then 'no' else 'yes') 
AS new FROM `video` as v
LIMIT 0, 25' at line 1

Answer 1

这不是MySQL中IF的正确语法。试试这样：

SELECT v.*,
    IF(from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY, 'yes', 'no') AS new
FROM `video` as v

Answer 2

尝试CASE声明：

SELECT v.*, 
    CASE WHEN from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY 
         THEN 'Yes' 
         ELSE 'No' 
    END AS new 
FROM `video`

这是在SQL中执行此操作的ansi标准方法。

Answer 3

尝试使用案例

SELECT v.*
    ,case
        when (from_unixtime(v.upload_date) < NOW() - INTERVAL 2 DAY) then 'yes'
        else 'no')
     end AS new
FROM `video` as v

使用if条件的Mysql数据库查询

3 个答案: